a. Construct a 90% confidence interval estimate for the population mean time wasted in a day due to outdated communication technologies. Sus Round to two decimal places as needed.) . Construct a 99% confidence interval estimate for the population proportion of health care clinicians who cite nefficiency of pagers as the reason for the wasted time.

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A consulting firm wants to study communication deficiencies in the health care industry. A random sample of 66 health
care clinicians reveals the following:
Time wasted in a day due to outdated communication technologies: X = 36 minutes, S = 9 minutes. Twenty-nine
health care clinicians cite inefficiency of pagers as the reason for the wasted time.
Complete parts (a) and (b) below.
a. Construct a 90% confidence interval estimate for the population mean time wasted in a day due to outdated
communication technologies.
sus Π
(Round to two decimal places as needed.)
b. Construct a 99% confidence interval estimate for the population proportion of health care clinicians who cite
inefficiency of pagers as the reason for the wasted time.
Σπς
(Round to four decimal places as needed.)
Transcribed Image Text:A consulting firm wants to study communication deficiencies in the health care industry. A random sample of 66 health care clinicians reveals the following: Time wasted in a day due to outdated communication technologies: X = 36 minutes, S = 9 minutes. Twenty-nine health care clinicians cite inefficiency of pagers as the reason for the wasted time. Complete parts (a) and (b) below. a. Construct a 90% confidence interval estimate for the population mean time wasted in a day due to outdated communication technologies. sus Π (Round to two decimal places as needed.) b. Construct a 99% confidence interval estimate for the population proportion of health care clinicians who cite inefficiency of pagers as the reason for the wasted time. Σπς (Round to four decimal places as needed.)
The diameter of a brand of tennis balls is approximately normally distributed, with a mean of 2.65 inches and a standard
deviation of 0.06 inch. A random sample of 12 tennis balls is selected. Complete parts (a) through (d) below.
a. What is the sampling distribution of the mean?
O A. Because the population diameter of tennis balls is approximately normally distributed, the sampling distribution
of samples of size 12 will also be approximately normal.
B. Because the population diameter of tennis balls is approximately normally distributed, the sampling distribution
of samples of size 12 will not be approximately normal.
C. Because the population diameter of tennis balls is approximately normally distributed, the sampling distribution
of samples of size 12 will be the uniform distribution.
D. Because the population diameter of tennis balls is approximately normally distributed, the sampling distribution
of samples of size 12 cannot be found.
b. What is the probability that the sample mean is less than 2.64 inches?
P(X<2.64)=
(Round to four decimal places as needed.)
c. What is the probability that the sample mean is between 2.63 and 2.67 inches?
P(2.63 < X<2.67) =
(Round to four decimal places as needed.)
Transcribed Image Text:The diameter of a brand of tennis balls is approximately normally distributed, with a mean of 2.65 inches and a standard deviation of 0.06 inch. A random sample of 12 tennis balls is selected. Complete parts (a) through (d) below. a. What is the sampling distribution of the mean? O A. Because the population diameter of tennis balls is approximately normally distributed, the sampling distribution of samples of size 12 will also be approximately normal. B. Because the population diameter of tennis balls is approximately normally distributed, the sampling distribution of samples of size 12 will not be approximately normal. C. Because the population diameter of tennis balls is approximately normally distributed, the sampling distribution of samples of size 12 will be the uniform distribution. D. Because the population diameter of tennis balls is approximately normally distributed, the sampling distribution of samples of size 12 cannot be found. b. What is the probability that the sample mean is less than 2.64 inches? P(X<2.64)= (Round to four decimal places as needed.) c. What is the probability that the sample mean is between 2.63 and 2.67 inches? P(2.63 < X<2.67) = (Round to four decimal places as needed.)
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