a. Consider the interval between x = -8 and x = -3. Explain why the product of the linear factors results in g(x) being negative and why the function changes from decreasing to increasing. the new The graph shows the product of the linear factors point (-1.5,-2.25). X. -5 fix) = x +3 -5 4. Analyze two intervals. the product of the linear factors results in g(x) being positive and why the function is decreasing. b. Consider the interval between x = -3 and x = 0. Explam

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Please explain
b. Consider the interval between x = -3 and x = 0. Explain why
and why the function changes from decreasing to increasing.
at
Suppe
point (-1.5,-2.25).
5. TH
pc
th
15
L-5
fix) = x+ 3
4. Analyze two intervals.
a. Consider the interval between x = -8 and x = -3. Explainu
the product of the linear factors results in g(x) being positi
and why the function is decreasing.
6.
the product of the linear factors results in g(x) being nega
7.
O Carnegie Learning, Inc.
Transcribed Image Text:b. Consider the interval between x = -3 and x = 0. Explain why and why the function changes from decreasing to increasing. at Suppe point (-1.5,-2.25). 5. TH pc th 15 L-5 fix) = x+ 3 4. Analyze two intervals. a. Consider the interval between x = -8 and x = -3. Explainu the product of the linear factors results in g(x) being positi and why the function is decreasing. 6. the product of the linear factors results in g(x) being nega 7. O Carnegie Learning, Inc.
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