a. Compute the outward flux across the quarter circle C: r(t)= (14 cos t, 14 sint) for Osts ¹2 The outward flux is X b. Compute the outward flux across the quarter circle C: r(t) = (14 cos t, 14 sin t) for Osts 2 The outward flux is c. Explain why the flux across the quarter circle in the third quadrant equals the flux computed in part (a). The normal vector in the third quadrant is 3 the normal vector in the first quadrant and the vector field in the third quadrant is Consider the vector field F= (y,x) shown on the right. d. Explain why the flux across the quarter circle in the fourth quadrant equals the flux computed in part (b). The normal vector in the fourth quadrant is 1 the normal vector in the second quadrant and the vector field in the fourth quadrant is e. What is the outward flux across the full circle? The outward flux is the vector field in the first quadrant, so their the vector field in the second quadrant, so their Thus, the flux is identical. Thus, the flux is identical.
a. Compute the outward flux across the quarter circle C: r(t)= (14 cos t, 14 sint) for Osts ¹2 The outward flux is X b. Compute the outward flux across the quarter circle C: r(t) = (14 cos t, 14 sin t) for Osts 2 The outward flux is c. Explain why the flux across the quarter circle in the third quadrant equals the flux computed in part (a). The normal vector in the third quadrant is 3 the normal vector in the first quadrant and the vector field in the third quadrant is Consider the vector field F= (y,x) shown on the right. d. Explain why the flux across the quarter circle in the fourth quadrant equals the flux computed in part (b). The normal vector in the fourth quadrant is 1 the normal vector in the second quadrant and the vector field in the fourth quadrant is e. What is the outward flux across the full circle? The outward flux is the vector field in the first quadrant, so their the vector field in the second quadrant, so their Thus, the flux is identical. Thus, the flux is identical.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
16

Transcribed Image Text:π
a. Compute the outward flux across the quarter circle C: r(t)= (14 cos t, 14 sin t) for Osts. 2
The outward flux is
b. Compute the outward flux across the quarter circle C: r(t)= (14 cos t, 14 sin t) for Osts
The outward flux is
c. Explain why the flux across the quarter circle in the third quadrant equals the flux computed in part (a).
The normal vector in the third quadrant is
d. Explain why the flux across the quarter circle in the fourth quadrant equals the flux computed in part (b).
The normal vector in the fourth quadrant is
e. What is the outward flux across the full circle?
The outward flux is.
Consider the vector field F= (y,x) shown on the right.
the normal vector in the first quadrant and the vector field in the third quadrant is
Y
the normal vector in the second quadrant and the vector field in the fourth quadrant is
the vector field in the first quadrant, so their
the vector field in the second quadrant, so their
Thus, the flux is identical.
Thus, the flux is identical.
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