A. Can you draw the animation of Merge sort: given an unsorted array of size 10, show the divide and conquer technique b. What is Running time for Merge Sort: O(nlogn) such that n is the size of the array:

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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A. Can you draw the animation of Merge sort: given an unsorted array of size 10, show the divide and
conquer technique
b. What is Running time for Merge Sort: O(nlogn) such that n is the size of the
array: 
Reference code attached

# Implementing Merge Sort in Java

## Overview

This page explains the implementation of the Merge Sort algorithm in Java. This algorithm is widely used for sorting arrays by dividing the array into halves, sorting them, and then merging them back together.

## Code Explanation

### MergeSort Class

```java
public class MergeSort {
    /** The method for sorting the numbers */
    public static void mergeSort(int[] list) {
        if (list.length > 1) {
            // Merge sort the first half
            int[] firstHalf = new int[list.length / 2];
            System.arraycopy(list, 0, firstHalf, 0, list.length / 2);
            mergeSort(firstHalf);

            // Merge sort the second half
            int secondHalfLength = list.length - list.length / 2;
            int[] secondHalf = new int[secondHalfLength];
            System.arraycopy(list, list.length / 2, secondHalf, 0, secondHalfLength);
            mergeSort(secondHalf);

            // Merge firstHalf with secondHalf into list
            merge(firstHalf, secondHalf, list);
        }
    }
```

#### Method: `mergeSort`

- **Purpose**: Sorts an array using the Merge Sort algorithm.
- **Parameters**: `int[] list` - the array to be sorted.
- **Process**:
  - If the length of the list is greater than 1, divide it into two halves.
  - Recursively call `mergeSort` on each half.
  - Merge the sorted halves back into the original list.

### Merge Two Sorted Lists

```java
    /** Merge two sorted lists */
    public static void merge(int[] list1, int[] list2, int[] temp) {
        int current1 = 0; // Current index in list1
        int current2 = 0; // Current index in list2
        int current3 = 0; // Current index in temp

        while (current1 < list1.length && current2 < list2.length) {
            if (list1[current1] < list2[current2])
                temp[current3++] = list1[current1++];
            else
                temp[current3++] = list2[current2++];
        }

        while (current1 < list1.length)
            temp[current3++] = list1[current1++];

        while (current2 < list2.length)
            temp[current3++] =
Transcribed Image Text:# Implementing Merge Sort in Java ## Overview This page explains the implementation of the Merge Sort algorithm in Java. This algorithm is widely used for sorting arrays by dividing the array into halves, sorting them, and then merging them back together. ## Code Explanation ### MergeSort Class ```java public class MergeSort { /** The method for sorting the numbers */ public static void mergeSort(int[] list) { if (list.length > 1) { // Merge sort the first half int[] firstHalf = new int[list.length / 2]; System.arraycopy(list, 0, firstHalf, 0, list.length / 2); mergeSort(firstHalf); // Merge sort the second half int secondHalfLength = list.length - list.length / 2; int[] secondHalf = new int[secondHalfLength]; System.arraycopy(list, list.length / 2, secondHalf, 0, secondHalfLength); mergeSort(secondHalf); // Merge firstHalf with secondHalf into list merge(firstHalf, secondHalf, list); } } ``` #### Method: `mergeSort` - **Purpose**: Sorts an array using the Merge Sort algorithm. - **Parameters**: `int[] list` - the array to be sorted. - **Process**: - If the length of the list is greater than 1, divide it into two halves. - Recursively call `mergeSort` on each half. - Merge the sorted halves back into the original list. ### Merge Two Sorted Lists ```java /** Merge two sorted lists */ public static void merge(int[] list1, int[] list2, int[] temp) { int current1 = 0; // Current index in list1 int current2 = 0; // Current index in list2 int current3 = 0; // Current index in temp while (current1 < list1.length && current2 < list2.length) { if (list1[current1] < list2[current2]) temp[current3++] = list1[current1++]; else temp[current3++] = list2[current2++]; } while (current1 < list1.length) temp[current3++] = list1[current1++]; while (current2 < list2.length) temp[current3++] =
The image presents two horizontal arrays:

1. **Array 1**:
   - Contains the numbers: 19, 29, 50, 70, 92, 96, 98
   - A label "current1" in red with a green arrow points to the first element, 19.

2. **Array 2**:
   - Contains the numbers: 11, 24, 33, 42, 49, 66, 78
   - A label "current2" in red with a green arrow points to the first element, 11.

Each array is represented as a sequence of boxes containing numbers, aligned in a single row. The labels with arrows indicate the current focus or active position within each array.
Transcribed Image Text:The image presents two horizontal arrays: 1. **Array 1**: - Contains the numbers: 19, 29, 50, 70, 92, 96, 98 - A label "current1" in red with a green arrow points to the first element, 19. 2. **Array 2**: - Contains the numbers: 11, 24, 33, 42, 49, 66, 78 - A label "current2" in red with a green arrow points to the first element, 11. Each array is represented as a sequence of boxes containing numbers, aligned in a single row. The labels with arrows indicate the current focus or active position within each array.
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