a. Calculate the proportion of survey respondents who have answered that they are in favor ofpeople having a right to abortion for any reason, using answers to Question #15 (Q15).b. Calculate a 95% confidence interval for the proportion in favor of the right to abortion forany reason in the surveyed population. Interpret your results.c. Suppose that the proportion of Americans who support abortion is 61%. Is the proportion infavor of abortion access in the surveyed population different from the proportion in the generalpopulation? Conduct a hypothesis test to evaluate this question, using a significance level ofa=.05. State your conclusion in English. Note: You do NOT need the size of the U.S. populationto answer this question.d. Discuss whether the data meet the sample size requirements for the procedures you used inpart b and c 01511 1: in favor1 2: against1111111111111111111111111111111212111111111111121111

The question is about confidence interval and proportion Given : 1 : In favor , 2 : against To…

Answered: a. Calculate the proportion of survey…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A CBS News poll conducted July 29–August 4, 2014, surveyed 1344 randomly selected American adults. Of those surveyed, 726 say that their sympathies in the Middle East situation lie more with the Israelis than with the Palestinians. Give a 95% confidence interval for the proportion of all American adults whose sympathies in the Middle East situation lie more with the Israelis than with the Palestinians. (__Answer 1__, __Answer 2__) Give your answers to 3 decimal places.
46. A sample of 5,324 Americans were asked about what matters most to them in a place to live. Thirty-seven percent of the respondents felt that good job opportunities matter most. a. Construct the 90% confidence interval for the proportion of Americans who feel that good job opportunities matter most in a place to live. b. Construct the 99% confidence interval for the proportion of Americans who feel that good job opportunities matter most in a place to live. c Which of the above two intervals has a higher margin of error? Explain why.
solve the following questions correctly, please.
The figure to the right shows the results of a survey in which 1005 adults from Country A, 1023 adults from Country B, 995 adults from Country C, 1020 adults from Country D, and 1012 adults from Country E were asked whether national identity is strongly tied to birthplace. Country A37%22%27%49%Country BCountry CCountry DCountry E10% Construct a 99% confidence interval for the population proportion of adults who say national identity is strongly tied to birthplace for each country listed. Question content area bottom Part 1 The 99% confidence interval for the proportion of adults from Country A who say national identity is strongly tied to birthplace is (enter your response here ,enter your response here ). (Round to three decimal places as needed.)
The Vegetarian Resource Group commissioned Harris Poll in 2016 to conduct a nationally representative online poll of 2,015 adults aged 18 and over. They found that 3.3% of the respondents identified as vegetarian. a. Construct and interpret a 95% confidence interval for the proportion of vegetarians. b. Based on the interval what kind of evidence do you expect to have for the alternative two-sided hypothesis test? explain. I do not understand question b
Kit and Casey are each attempting to estimate the proportion of college students who can play at least one musical instrument. They each survey a different random sample of college students, and in each sample, the proportion who can play at least one musical instrument is 0.35. Kit and Casey each use their sample data to construct a confidence interval. Kit's interval is from 0.308 to 0.372 and Casey's interval is from 0.318 to 0.382. One of these intervals was computed correctly, but the other was not. Which interval must be incorrect? O Kit's interval must be incorrect. O It's impossible to answer this question without knowing the sample sizes. O It's impossible to answer this question without knowing the sample sizes or the level of confidence used for each interval. O Casey's interval must be incorrect. O It's impossible to answer this question without knowing the level of confidence used for each interval.
Suppose you calculate a 95% and 90% confidence interval for the true proportion of college students with student loan using the same data set. Which of the following must be true? a) The 95% confidence interval is wider than the 90% confidence interval. b) The 95% confidence interval is the same length as the 90% confidence interval. c) The 95% confidence interval is narrower than the 90% confidence interval. d) There is no way to tell from the given information.
Which of the following would be a correct interpretation of an 87% confidence interval for the true proportion of students who do aerobics? A) We are 87% confident that the true proportion of students who do aerobics is between 28.8% and 39.9%. B) We are 87% confident that the true average of students who do aerobics is between 28.8% and 39.9%. C) We are 95% confident that the true proportion of students who do aerobics is between 28.8% and 39.9%. D) We are 87% confident that the true proportion of students who do aerobics is between 27.3% and 41.7%.
Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
In September 2011, Gallup surveyed 1,004 American adults and asked them whether they blamed Barack Obama a great deal, a moderate amount, not much, or not at all for U.S. economic problems. The results showed that 53% of respondents blamed Barack Obama a great deal or a moderate amount. Calculate the 99% confidence interval for the proportion of all American adults who blame Barack Obama a great deal or a moderate amount for U.S. economic problems. O (0.504, 0.556) O (0.499, 0.561) O (0.489, 0.571) O The confidence interval cannot be determined from the information given.
The dean of students at a large college is interested in learning about their opinions regarding the percentage of first-year students who should be given parking privileges in the main lot. He sends out an email survey to all students about this issue. A large number of first-year students reply but very few sophomores, juniors, and seniors reply. Based on the responses he receives, he constructs a 90% confidence interval for the true proportion of students who believe first-year students should be given parking privileges in the main lot to be (0.71, 0.79). Which of the following may have an impact on the confidence interval, but is not accounted for by the margin of error? response bias O nonresponse bias O sampling variation O undercoverage bias
2. According to the website Rotten Tomatoes, 94% of people who watched the Netflix show Stranger Things liked it. Since UR students tend to be scientifically minded, we hypothesize that less than 94% of UR students like the show. Out of 219 surveyed UR students, 198 indicated they like Stranger Things. Use the built in prop.test() function to: a. Construct a 90% confidence interval for the proportion of UR students who like Stranger Things. b. Test at the a=0.10 significance level whether the proportion of students who like Stranger Things is LESS THAN 0.94. What conclusion do you reach?

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