a. Calculate the centerline, the upper control limit (UCL), and the lower control limit (LCL) for the I chart if samples of 15 boxes are taken. (Round the value for the centerline to the nearest whole number and the values for the UCL and LCL to 3 decimal places.) Centerline Upper Control Limit Lower Control Limit b. Analysts obtain the following sample means after a recent inspection of the production process. Can they conclude that the process is under control? Xj = 14.8 X2 = 14.4 X3 = 13.4 X4 = 14.6 Xs = 14.1 X6 = 14.7 O Yes , because all sample means lie within the control limits , and there is no systematic pattern. O Yes , because some sample means lie outside the control limits. O No , because some sample means lie outside the control limits. O No , because even though all sample means lie within the control limits , there is a negative trend.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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ISBN:9780079039897
Author:Carter
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Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 2GP
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**A production process is designed to fill boxes with an average of 14 ounces of cereal. The population of filling weights is normally distributed with a standard deviation of 2 ounces.**

### a. Calculate the centerline, the upper control limit (UCL), and the lower control limit (LCL) for the \(\overline{x}\) chart if samples of 15 boxes are taken. 

*(Round the value for the centerline to the nearest whole number and the values for the UCL and LCL to 3 decimal places.)*

#### Table:

|                            |          |
|----------------------------|----------|
| Centerline                 |          |
| Upper Control Limit        |          |
| Lower Control Limit        |          |

---

### b. Analysts obtain the following sample means after a recent inspection of the production process. Can they conclude that the process is under control?

\[
\overline{x}_1 = 14.8 \quad \overline{x}_2 = 14.4 \quad \overline{x}_3 = 13.4 \quad \overline{x}_4 = 14.6 \quad \overline{x}_5 = 14.1 \quad \overline{x}_6 = 14.7
\]

#### Options:

- ○ Yes, because all sample means lie within the control limits, and there is no systematic pattern.
- ○ Yes, because some sample means lie outside the control limits.
- ○ No, because some sample means lie outside the control limits.
- ○ No, because even though all sample means lie within the control limits, there is a negative trend.
Transcribed Image Text:**A production process is designed to fill boxes with an average of 14 ounces of cereal. The population of filling weights is normally distributed with a standard deviation of 2 ounces.** ### a. Calculate the centerline, the upper control limit (UCL), and the lower control limit (LCL) for the \(\overline{x}\) chart if samples of 15 boxes are taken. *(Round the value for the centerline to the nearest whole number and the values for the UCL and LCL to 3 decimal places.)* #### Table: | | | |----------------------------|----------| | Centerline | | | Upper Control Limit | | | Lower Control Limit | | --- ### b. Analysts obtain the following sample means after a recent inspection of the production process. Can they conclude that the process is under control? \[ \overline{x}_1 = 14.8 \quad \overline{x}_2 = 14.4 \quad \overline{x}_3 = 13.4 \quad \overline{x}_4 = 14.6 \quad \overline{x}_5 = 14.1 \quad \overline{x}_6 = 14.7 \] #### Options: - ○ Yes, because all sample means lie within the control limits, and there is no systematic pattern. - ○ Yes, because some sample means lie outside the control limits. - ○ No, because some sample means lie outside the control limits. - ○ No, because even though all sample means lie within the control limits, there is a negative trend.
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