Can someone please Help me with the red portion, I manage to use my calculator and place both functions next to one another f(x)= 2500(1.04)^n and g(x)= 4000(1.03)^n. Please help and explain. Yn+1 =where n is in years. If the initial population is yo3₁ = 4120 1.03(4000) = 4/20a. A population of herbivores satisfies the growth equation1.03yn,Y3 = 4370.908 1.03(4120) = 4370.908b. A competing group of herbivores satisfies the growth equation1.04zn.Zn+1If the initial population is zo==== 4000, then determine the populations y₁ and y3.4006 (1.03)"=2500, then determine how long it takes for this population to double.Doubling time = 40 yearsWhat is the population of these herbivores after 10 years?Z10 37002500 (1.04) ¹0 = 2500 (1.04)"c. Find when the two populations are equal. What is their population at this time?Populations are equal in 10 yearsPopulation at this time is 3700

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a. A population of herbivores satisfies the growth equation Yn+1 = 1.03yn, where n is in years. If the initial population is yo = 4000, then determine the populations y₁ and y3. Y1 = 4120 1.03(4066) = 4/20 4006 (1.03) Y3 = 4370.908 1.034/20) = 4370.908 b. A competing group of herbivores satisfies the growth equation Zn+1 = 1.04zn. If the initial population is zo = 2500, then determine how long it takes for this population to double. Doubling time = 40 years What is the population of these herbivores after 10 years? 210 3700 2500 (1.04)¹0 2500 (1.04)" c. Find when the two populations are equal. What is their population at this time? Populations are equal in 10 years

a. A population of herbivores satisfies the growth equation Yn+1 = 1.03yn, where n is in years. If the initial population is yo = 4000, then determine the populations y₁ and y3. Y1 = 4120 1.03(4066) = 4/20 4006 (1.03) Y3 = 4370.908 1.034/20) = 4370.908 b. A competing group of herbivores satisfies the growth equation Zn+1 = 1.04zn. If the initial population is zo = 2500, then determine how long it takes for this population to double. Doubling time = 40 years What is the population of these herbivores after 10 years? 210 3700 2500 (1.04)¹0 2500 (1.04)" c. Find when the two populations are equal. What is their population at this time? Populations are equal in 10 years

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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Question

Can someone please Help me with the red portion, I manage to use my calculator and place both functions next to one another f(x)= 2500(1.04)^n and g(x)= 4000(1.03)^n. Please help and explain.

Yn+1 =
where n is in years. If the initial population is yo
3₁ = 4120 1.03(4000) = 4/20
a. A population of herbivores satisfies the growth equation
1.03yn,
Y3 = 4370.908 1.03(4120) = 4370.908
b. A competing group of herbivores satisfies the growth equation
1.04zn.
Zn+1
If the initial population is zo
=
=
=
= 4000, then determine the populations y₁ and y3.
4006 (1.03)"
=
2500, then determine how long it takes for this population to double.
Doubling time = 40 years
What is the population of these herbivores after 10 years?
Z10 3700
2500 (1.04) ¹0 = 2500 (1.04)"
c. Find when the two populations are equal. What is their population at this time?
Populations are equal in 10 years
Population at this time is 3700

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