A).  A COMPANY IS CONDUCTING AN ONLINE SURVEY OF RANDOMLY SELECTED INDIVIDUALS TO           DETERMINE HOW FREQUENT THEY RECYCLE.  SO FAR, 2451 PEOPLE HAVE BEEN SURVEYED. THE FREQUENCY DISTRIBUTION SHOWS THE RESULTS. WHAT IS THE PROBABILITY THAT THE NEXTPERSON SURVEYED RARELY RECYCLES? RESPONSE NUMBER OF TIMES, f Always 1054 Often 613 Sometimes 417 Rarely 196 Never 171   Total = 2451   B).  USE THE CONCEPT OF COMPLEMENTARY EVENTS TO        DETERMINE:  IF THE PROBABILITY OF A PERSON GETTING        SICK IS 5/9.  WHAT IS THE PROBABILITY OF THE SAME        PERSON NOT GETTING SICK?        USE THE FORMULA:   P(SICK) + P (NOT SICK) = 1

A First Course in Probability (10th Edition)
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Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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A).  A COMPANY IS CONDUCTING AN ONLINE SURVEY OF RANDOMLY SELECTED INDIVIDUALS TO           DETERMINE HOW FREQUENT THEY

RECYCLE.  SO FAR, 2451 PEOPLE HAVE BEEN SURVEYED. THE

FREQUENCY DISTRIBUTION SHOWS THE RESULTS. WHAT IS THE PROBABILITY THAT THE NEXTPERSON SURVEYED RARELY RECYCLES?

RESPONSE

NUMBER OF TIMES, f

Always

1054

Often

613

Sometimes

417

Rarely

196

Never

171

 

Total = 2451

 

B).  USE THE CONCEPT OF COMPLEMENTARY EVENTS TO

       DETERMINE:  IF THE PROBABILITY OF A PERSON GETTING

       SICK IS 5/9.  WHAT IS THE PROBABILITY OF THE SAME

       PERSON NOT GETTING SICK?

       USE THE FORMULA:   P(SICK) + P (NOT SICK) = 1

 

 

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