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A. 6. 104 g of H,0 (c= 4.184 J/g.K) is heated from 283 K to 308 K 1) Change in temperature (AT) = • Unit = 2) Heat (q) is calculated using the formula = 3) Heat (q) produced during the process is = • Unit =

A. 6. 104 g of H,0 (c= 4.184 J/g.K) is heated from 283 K to 308 K 1) Change in temperature (AT) = • Unit = 2) Heat (q) is calculated using the formula = 3) Heat (q) produced during the process is = • Unit =

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A. 6. 104 g of H_0 (c= 4.184 J/g.K) is heated from 283 K to 308 K 1) Change in temperature (AT) = • Unit = 2) Heat (q) is calculated using the formula = 3) Heat (q) produced during the process is = • Unit = B. Two iron bolts of equal mass, one at 245 K (T1initial) and other at 288 K (T2initial) are placed in an insulated container. Heat capacity of the container is negligible. Heat capacity of iron (c1) is o.450 J/g.K. 1) The final temperature (TAnal) is calculated using the formula = 2) Final temperature (Tfinal) is =| : Unit =
Transcribed Image Text:A. 6. 104 g of H_0 (c= 4.184 J/g.K) is heated from 283 K to 308 K 1) Change in temperature (AT) = • Unit = 2) Heat (q) is calculated using the formula = 3) Heat (q) produced during the process is = • Unit = B. Two iron bolts of equal mass, one at 245 K (T1initial) and other at 288 K (T2initial) are placed in an insulated container. Heat capacity of the container is negligible. Heat capacity of iron (c1) is o.450 J/g.K. 1) The final temperature (TAnal) is calculated using the formula = 2) Final temperature (Tfinal) is =| : Unit =
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