What will be the result shear flow of the object?a. 207,967.94 N/mb. 208,968.98 N/mc. 209,978.96 N/md. 209,979.00 N/m ### Educational Website Transcription**Image Description**The provided image is a handwritten set of calculations related to stress analysis in a mechanical component. Below is a detailed transcription and explanation of the content, including a diagram and mathematical equations.---**Diagram**A diagram of a mechanical component is shown. It is a rectangular bar with a semi-circular end. The dimensions and details in the diagram are as follows:- Height (H): 20 mm- Length (L): 12 cm (120 mm)- Radius (R) of the semi-circular end: 20 mm- A line is labeled "Q" intersecting vertically in the middle of the semi-circular portion.**Problem Details**- **Force Applied (T):** 408 N- **Twisting Moment (M):** 12 Nm- **Shear Modulus (G):** 28 GPa---**Step-by-Step Calculation**1. **Calculation of the Cross-Sectional Area (A)** \[ A = H \cdot L + \pi \cdot \left(\frac{D}{2}\right)^2 \] Given: \[ H = 20 \, \text{mm}, \quad L = 120 \, \text{mm}, \quad \text{and} \quad D = 40 \, \text{mm} \] Substitution: \[ A = (20 \times 120) + \pi \left( \frac{40}{2} \right)^2 \] \[ A = 2400 + \pi (20)^2 \] \[ A = 2400 + 1256.64 \approx \boxed{3657.08 \, \text{mm}^2} \]2. **Calculation of the Median Line Length (S)** \[ S = 2L + \frac{\pi D}{2} \] Given: \[ L = 120 \, \text{mm}, \quad \text{and} \quad D = 40 \, \text{mm} \] Substitution: \[ S = 2(120) + \frac{\pi \cdot 40}{2} \] \[ S = This diagram depicts a geometric shape consisting of a rectangle with a semicircular end. The measurements provided are as follows:- The rectangular part has a length of 40 mm and a height of 20 mm.- The semicircular end has a radius of 10 mm.- Additionally, there are dotted lines indicating the internal boundary of the shape which is uniformly offset from the outer boundary.Key measurements:- The total horizontal length from one end of the rectangle to the curved edge of the semicircle is 80 mm.- The internal offset from the outer boundary is 2 mm.This diagram can be utilized to understand geometric shapes, properties of combined shapes (rectangles and semicircles), and methods to calculate areas or perimeters of such composite figures.

Answered: Image /qna-images/answer/3f1a683c-e9bf-415a-a489-b69189bcf926.jpg

Answered: a. 207,967.94 N/m b. 208,968.98 N/m c.…

Engineering

Mechanical Engineering

a. 207,967.94 N/m b. 208,968.98 N/m c. 209,978.96 N/m d. 209,979.00 N/m

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

What will be the result shear flow of the object?

a. 207,967.94 N/m

b. 208,968.98 N/m

c. 209,978.96 N/m

d. 209,979.00 N/m

### Educational Website Transcription

**Image Description**

The provided image is a handwritten set of calculations related to stress analysis in a mechanical component. Below is a detailed transcription and explanation of the content, including a diagram and mathematical equations.

---

**Diagram**

A diagram of a mechanical component is shown. It is a rectangular bar with a semi-circular end. The dimensions and details in the diagram are as follows:
- Height (H): 20 mm
- Length (L): 12 cm (120 mm)
- Radius (R) of the semi-circular end: 20 mm
- A line is labeled "Q" intersecting vertically in the middle of the semi-circular portion.

**Problem Details**

- **Force Applied (T):** 408 N
- **Twisting Moment (M):** 12 Nm
- **Shear Modulus (G):** 28 GPa

---

**Step-by-Step Calculation**

1. **Calculation of the Cross-Sectional Area (A)**

\[
A = H \cdot L + \pi \cdot \left(\frac{D}{2}\right)^2
\]

Given:
\[
H = 20 \, \text{mm}, \quad L = 120 \, \text{mm}, \quad \text{and} \quad D = 40 \, \text{mm}
\]

Substitution:
\[
A = (20 \times 120) + \pi \left( \frac{40}{2} \right)^2
\]
\[
A = 2400 + \pi (20)^2
\]
\[
A = 2400 + 1256.64 \approx \boxed{3657.08 \, \text{mm}^2}
\]

2. **Calculation of the Median Line Length (S)**

\[
S = 2L + \frac{\pi D}{2}
\]

Given:
\[
L = 120 \, \text{mm}, \quad \text{and} \quad D = 40 \, \text{mm}
\]

Substitution:
\[
S = 2(120) + \frac{\pi \cdot 40}{2}
\]
\[
S =

This diagram depicts a geometric shape consisting of a rectangle with a semicircular end. The measurements provided are as follows:

- The rectangular part has a length of 40 mm and a height of 20 mm.
- The semicircular end has a radius of 10 mm.
- Additionally, there are dotted lines indicating the internal boundary of the shape which is uniformly offset from the outer boundary.

Key measurements:
- The total horizontal length from one end of the rectangle to the curved edge of the semicircle is 80 mm.
- The internal offset from the outer boundary is 2 mm.

This diagram can be utilized to understand geometric shapes, properties of combined shapes (rectangles and semicircles), and methods to calculate areas or perimeters of such composite figures.

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