A. 0x2000 B. 0x2008 O C. 0x2010 D. 0x2018 O E. 0x2020 F. 0x2028 arte
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Transcribed Image Text:**Question:**
What value is in `z` after the code above runs?
**Options:**
- A. 0x2000
- B. 0x2008
- C. 0x2010
- D. 0x2018
- E. 0x2020
- F. 0x2028
- G. 0x2030

Transcribed Image Text:**Consider the following code:**
```c
int x = 0x2020;
int *y = &x;
int **z = &y;
*y += 8;
int w = **z;
```
Suppose the compiler puts `x` at address `0x2000`, `y` at address `0x2008`, `z` at address `0x2010`, and `w` at address `0x2018`.
Use this code to answer the next 4 questions.
---
The code snippet exhibits the use of pointers and pointer manipulation in C programming. Here’s a brief explanation:
- `x` is assigned the hexadecimal value `0x2020`.
- `y` is a pointer that stores the address of `x`.
- `z` is a pointer to a pointer, storing the address of `y`.
- The line `*y += 8;` increments the value pointed to by `y` (i.e., `x`) by 8.
- `w` stores the value pointed to by `z`, which is the same as `x` now increased by 8.
The memory addresses shown are just hypothetical and help illustrate where each variable resides during execution.
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