A. 0.085 OB. 0.18 0.143 0.193 A A A 0.143 0.181 0.181 0.123 O C. Calculate the test statistic. The test statistic is (Round to two decimal places as needed.) Calculate the P-value. P-value = (Round to three decimal places as needed.) d) State the conclusion. 0.123 OA. Because the P-value is so high, there is not sufficient evidence that the proportion of housing units that are vacant in this county differs from that in the country as a whole. OB. Because the P-value is so low, there is not sufficient evidence that the proportion of housing units that are vacant in this county differs from that in the country as a whole. OC. Because the P-value is so low, there is evidence that the proportion of housing units that are vacant in this county differs from that in the country as a whole.

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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According to a recent census, 14.3% of all housing units in a
certain country are vacant. A county supervisor wonders if her
county is different from this. She randomly selects 893 housing
units in her county and finds that 162 of the housing units are
vacant. Complete parts a through d below.
a) State the hypotheses.
Let the proportion of housing units in the county that are vacant
be denoted by p. Choose the correct answer below.
OA. Ho: p<0.143
HA: P = 0.143
O C. Ho: p=0.143
HA: P<0.143
OB. Ho: p=0.143
HA: P = 0.143
O D. Ho: p20.143
HA: P<0.143
b) Name the model and check appropriate conditions for a
hypothesis test.
What kind of test is this? Choose the correct answer below.
Two-proportion t-test
Difference in proportions test
Proportional t-test
O One-proportion z-test
Check the appropriate conditions for a hypothesis test. Select
the correct choice below and fill in the answer boxes within your
choice.
(Round to one decimal place as needed.)
successes and nqo =
than 10.
OA. The 893 housing units were a random sample from the
county of interest. 893 is likely less than 10% of all
housing units in the county. One expects npo =
failures, which are both more
OB. The 893 housing units were a random sample from the
county of interest. The standard deviation of p is less
than 0.5. One expects npo =
successes and
Transcribed Image Text:According to a recent census, 14.3% of all housing units in a certain country are vacant. A county supervisor wonders if her county is different from this. She randomly selects 893 housing units in her county and finds that 162 of the housing units are vacant. Complete parts a through d below. a) State the hypotheses. Let the proportion of housing units in the county that are vacant be denoted by p. Choose the correct answer below. OA. Ho: p<0.143 HA: P = 0.143 O C. Ho: p=0.143 HA: P<0.143 OB. Ho: p=0.143 HA: P = 0.143 O D. Ho: p20.143 HA: P<0.143 b) Name the model and check appropriate conditions for a hypothesis test. What kind of test is this? Choose the correct answer below. Two-proportion t-test Difference in proportions test Proportional t-test O One-proportion z-test Check the appropriate conditions for a hypothesis test. Select the correct choice below and fill in the answer boxes within your choice. (Round to one decimal place as needed.) successes and nqo = than 10. OA. The 893 housing units were a random sample from the county of interest. 893 is likely less than 10% of all housing units in the county. One expects npo = failures, which are both more OB. The 893 housing units were a random sample from the county of interest. The standard deviation of p is less than 0.5. One expects npo = successes and
K
According to a recent census, 14.3% of all housing units in a
certain country are vacant. A county supervisor wonders if her
county is different from this. She randomly selects 893 housing
units in her county and finds that 162 of the housing units are
vacant. Complete parts a through d below.
Choose the correct sketch below.
O A.
0.085
0.143
ANA
0.123
0.181
0.143
B.
0.18
Calculate the test statistic.
O C.
The test statistic is
(Round to two decimal places as needed.)
Calculate the P-value.
P-value =
(Round to three decimal places as needed.)
d) State the conclusion.
0.123
0.193
0.181
A. Because the P-value is so high, there is not sufficient
evidence that the proportion of housing units that are
vacant in this county differs from that in the country as a
whole.
OB. Because the P-value is so low, there is not sufficient
evidence that the proportion of housing units that are
vacant in this county differs from that in the country as a
whole.
C. Because the P-value is so low, there is evidence that
the proportion of housing units that are vacant in this
county differs from that in the country as a whole.
Transcribed Image Text:K According to a recent census, 14.3% of all housing units in a certain country are vacant. A county supervisor wonders if her county is different from this. She randomly selects 893 housing units in her county and finds that 162 of the housing units are vacant. Complete parts a through d below. Choose the correct sketch below. O A. 0.085 0.143 ANA 0.123 0.181 0.143 B. 0.18 Calculate the test statistic. O C. The test statistic is (Round to two decimal places as needed.) Calculate the P-value. P-value = (Round to three decimal places as needed.) d) State the conclusion. 0.123 0.193 0.181 A. Because the P-value is so high, there is not sufficient evidence that the proportion of housing units that are vacant in this county differs from that in the country as a whole. OB. Because the P-value is so low, there is not sufficient evidence that the proportion of housing units that are vacant in this county differs from that in the country as a whole. C. Because the P-value is so low, there is evidence that the proportion of housing units that are vacant in this county differs from that in the country as a whole.
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