A) zyz = 6x2 · fu · 6x²y+ 5yª · fwu · 6x²y B) zyz = 6x2 · fu + (2x³ – 1) · fuu + 5y4 · fwu · 6x²y C) zyz = 6x²y · (2x³ – 1) · fuu + 6x² · fu + 6x²y · fwu D) zym = 30x²y³ . fwu + (12x³y – 6æ²y) · fuu + 6x² · fu
A) zyz = 6x2 · fu · 6x²y+ 5yª · fwu · 6x²y B) zyz = 6x2 · fu + (2x³ – 1) · fuu + 5y4 · fwu · 6x²y C) zyz = 6x²y · (2x³ – 1) · fuu + 6x² · fu + 6x²y · fwu D) zym = 30x²y³ . fwu + (12x³y – 6æ²y) · fuu + 6x² · fu
Chapter5: Polynomial And Rational Functions
Section: Chapter Questions
Problem 27PT: Find the unknown value. 27. y varies jointly with x and the cube root of 2. If when x=2 and...
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Question
Let f be a function with continuous second partial derivatives and define:
image 1 first equation and two equations
From the above it is concluded that:
image 2
Transcribed Image Text:A) zyr = 6x² · fu · 6x²y+ 5yª · fwu · 6x²y
B) zyz = 6x2 . fu + (2a³ – 1) · fuu + 5y4 · fwu · 6x²y
C) zyz = 6a?y · (2x3 – 1) · fuu + 6x² · fu + 6x²y· fwru
D) zpz = 30x?y5 . fwu + (12x³y – 6x²y) · fuu + 6x² · fu
Transcribed Image Text:z = f (2x®y – y, y°)
u = 2a®y – y y w = y%
dz
= (203 – 1) · fu + 5y4 . fw
dy
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