A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Your program must define and call the following function. The function should return True if the input year is a leap year or False otherwise. def is_leap_year(user_year) Here is code so far. I am stuck on this one. It is failing out on the 2: Unit testkeyboard_arrow_up 0 / 2 is_leap_year(1913) 3: Unit testkeyboard_arrow_up 0 / 3 is_leap_year(1600) 4: Unit testkeyboard_arrow_up 0 / 3 is_leap_year(1900) Code below: def is_leap_year(user_year): if (user_year % 4) == 0: if(user_year % 100) == 0: if (user_year % 400) == 0: return True else: return False else: return True else: return False if __name__ == '__main__': user_year = int(float(input())) x = is_leap_year(user_year) if(x == True): print('%d is a leap year.'%(user_year)) else: print('%d is not a leap year. '%(user_year))
4.21 LAB: Leap year - functions
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:
1) The year must be divisible by 4
2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400
Some example leap years are 1600, 1712, and 2016.
Write a program that takes in a year and determines whether that year is a leap year.
Your program must define and call the following function. The function should return True if the input year is a leap year or False otherwise.
def is_leap_year(user_year)
Here is code so far. I am stuck on this one. It is failing out on the
def is_leap_year(user_year):
if (user_year % 4) == 0:
if(user_year % 100) == 0:
if (user_year % 400) == 0:
return True
else:
return False
else:
return True
else:
return False
if __name__ == '__main__':
user_year = int(float(input()))
x = is_leap_year(user_year)
if(x == True):
print('%d is a leap year.'%(user_year))
else:
print('%d is not a leap year. '%(user_year))
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