A = {x = Z | x= 6a + 1 for some a € Z} B = {y≤ Z | y = 126 + 7 for some b = Z} C = {z €Z|z= 12c5 for some c = Z}. (a) Disprove that AC B. (HINT: write the definition of “not a subet of” by negating the subset defintion.) (b) Is BCA? Do not prove, but give reasons for your answer. (c) Use the "element chasing" method to prove that B = C;

Q: D pls

A:

Q: 3

A:

Q: u(z) dr

A:

Q: A: ſe2Lnx dx

A: Given: ∫e2lnxdx Simplify the expression. ∫e2lnxdx=∫x2dx

Q: LCM 3 and 5

A:

Q: r A D C

A: We have given a diagram;

Q: Given sec 8= √ 2 what is cos?

A:

Q: Multiply. (ex − e−x)2

A: Here we multiply this:

Q: dA D

A:

Q: 13 dk

A: Given :      ∫e73k-13   dk

Q: 6 2/5 ÷ 4

A: Given query is to solve the expression.

Q: 2ez 2 da = eAr

A: Topic = Integration

Q: 2. In the figure above, m || n and y 5x. What is the value of y ?

A:

Q: 5 and 2/3 feet + 4 and 1/6 feet

A: Answer  - 5 and 2/3 feet +4 and 1/6 feet

Q: D P•

A: CT2=CA*CB

Q: Find

A:

Q: (x, 5), (2, 6) m = 3/4

A: Let the equation of line be y=mx + b  ...(i) We have m=3/4 = 0.75

Q: Luestic Given the circumference of the circle and the measure of the central angle ACB, find the…

A:

Q: ind the derivatve foo 9. 314 %3D

A: First do differentiate of power and then diffrenatiate the function.