A work sampling study requires 95% confidence level with 5% limit error. How many observations are required if the machine down time is 8%
Q: Of 500 random people surveyed, 72 were smokers. Find the 95% confidence interval. SE=0.0157
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Q: 37% from a sample of 3800 people are saving for retirement. Construct the confidence interval for…
A: Given that. Sample size n =3800 Sample proportion p^=37%=0.37
Q: What sample size is needed if a researcher needed to calculate the true proportion of individuals…
A: HERE , MOE = 0.01 confidence level = 95% here z-critical for 95% confidence level = 1.96 here use…
Q: Suppose you select a random sample of N=81, and find X = 50, and s = 9.9. Determine the 99%…
A: Given Mean=50 Standard deviations=9.9 n=81
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Q: If n = 108, a = 29 and o = 2.6, construct a 91% confidence interval. Give your answers to three…
A: Since we know population standard deviation, use z-distribution to find z-critical value.…
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A: A relative risk collates the risk of disease, injury, or death among one group with risk among other…
Q: There are many reasons adults use credit cards. A recent survey found that 66% of adults used credit…
A: 66% of adults use credit cards for convenience.Confidence level is 99% i.e., 0.99.Margin of error is…
Q: If n = 560 and X = 448, construct a 95% confidence interval for the population proportion, p. %3D…
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Q: A 95% confidence interval for a population mean was reported to be 134 to 142. If the population…
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Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…
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Q: a 95% confidence interval estimate for population mean is determined to be 75.38 to 86.52. if the…
A: We have to find the confidence level is reduced to 90%, the confidence interval will....
Q: The mean and the standard deviation of a normal population are 11,795 and 14054 respectively. If n=…
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Q: If n = 230 and X = 184, construct a 99% confidence interval for the population proportion, p.Give…
A: Given data n = 230 x = 184 sample proportion
Q: p'= α %4 || Margin of Error: E We are 87% confident that the proportion of Americans who feel that…
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Q: If n = 180 and X = 144, construct a 90% confidence interval for the population proportion, p. Give…
A: Solution: From the given information, X=144, n=180 and the confidence level is 0.90. The sample…
Q: The population mean of a set of data is unknown. The sample mean is 44, and the error bound for the…
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Q: If n=41n=41, ¯xx¯=36, and s=9s=9, find the margin of error for a 80% confidence level.
A: Answer - Given, Sample size n = 41, x = 36 and s = 9 80% confidence interval…
Q: Highway TPH Data. Estimate the 95th percentile and its upper 95% confidence limit for the highway…
A: The given data of TPH is shown below 19 119 40 129 48 114 23 92 79 43 19 62 118 230…
Q: Suppose you want to construct a confidence interval with a margin of error of 0.03 (3%). Find the…
A: The formula for calculating sample size is, n = z2*p^(1-p^)MOE2 Where, z is the z score (default…
Q: A researcher is interested in a 95% confidence interval. It is found to have a point estimate of 2.5…
A: From the provided information, Confidence level = 95% Point estimate = 2.5 Margin of error (E) = 0.6
Q: If n=27, (x-bar)=34, and s=3, find the margin of error at a 90% confidence leve Give your answer to…
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Q: If n=18, ¯x=x¯=34, and ss=15, construct a confidence interval at a 98% confidence level. Assume the…
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Q: If n=540 and (p-hat) = 0.13, construct a 99% confidence interval. Give your answers to three…
A: We have given that, Sample size (n) = 540 Sample proportion (p-hat) = 0.13 Then, We will find the…
Q: The number of successes and the sample size are given for a simple random sample from a population.…
A: Obtain the value of sample proportion. The value of sample proportion is obtained below: From the…
Q: If n=590 and p=0.93, construct a 90% confidence interval.
A: Express the expression for the confidence interval. C.I=p±Z*p(1-p)n Here, Z* is the critical value .…
Q: ou measure 46 dogs' weights, and find they have a mean weight of 32 ounces. Assume the sample…
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Q: construct a 99% confidence interval for the true population mean textbook weight.
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Q: Find a 95% confidence interval for the difference between full attendance students' Exam 5 score and…
A: We have given data, Less attendance Full attendance 90 96 90 96 60 100 50 99 69 88…
Q: You would like to estimate the proportion of all residents in favor of a new law with 98%…
A: The sample proportion is 0.30, margin of error is 0.06, and the confidence level is 98%. Computation…
Q: If n 28, = 37, and s = 6.2, construct a confidence interval at a 97% confidence level. Assume the…
A: Solution: The following information is given to us: s=6.2 n =28 A 97% confidence interval is…
Q: You measure 44 dogs' weights, and find they have a mean weight of 80 ounces. Assume the population…
A: You measure 44 dogs' weights, and find they have a mean weight of 80 ounces. Assume the population…
Q: 10. A 90% confidence interval is to be created to estimate the proportion of television viewers in a…
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Q: If Xbar=93, σ=13, and n=62, construct a 99% confidence interval estimate of the population…
A: Given that Sample size: n=62 Sample mean: x¯=93 Population standard deviation: σ=13 Confidence…
Q: If X=72, σ=13, and n=66, construct a 95% confidence interval estimate of the population…
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Q: If n=19, x= 47, and s = 8, find the margin of error at a 99% confidence level Give your answer to…
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Q: If n = 530 and X = 424, construct a 99% confidence interval for the population proportion, p. Give…
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Q: Assume that a sample is used to estimate a population proportion p. To find the 95% confidence…
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Q: The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to…
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Q: If N=480 and p̂ (p-hat) =0.88, find the margin of error at a 95% confidence level.
A: From the provided information, Sample size (n) = 480 p̂ (p-hat) =0.88 Confidence level = 95%
Q: Find the sample size of American adults you would need to predict the results of an election with a…
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Q: Construct a 90% confidence interval of the population proportion using the given information.…
A: x=240 n=300 p= 240/300 = 0.8 q = 1-p = 1-0.8 = 0.2
Q: A survey of 1000 people was conducted. 44% said they found it hard to adopt a child in the US.…
A: The given data is as follows:Sample size, Sample proportion, Margin of error, Confidence level, The…
Q: You measure 39 turtles' weights, and find they have a mean weight of 48 ounces. Assume the…
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- If X̅ = 65, ? = 20 ??? ? = 36, construct a 95% confidence interval estimate for the population mean, ?.You measure 27dogs' weights, and find they have a mean weight of 63 ounces. Assume the population standard deviation is 6.1 ounces. Based on this, what is the maximal margin of error associated with a 95% confidence interval for the true population mean dog weight.The estimated prevalence is 19% and the desired confidence is 93% with a margin of error of 4%. What is n=
- Exam 2 Math 200 Fall 2019-03 7. A random sample of 31 people in a nursing home had a mean systolic blood pressure of 153 mmHg and standard deviation of 35 mmHg. Find the 90% confidence interval for the mean blood pressure of people in the nursing home. Interpret the result. Name:MODULE 2 2. A sample of 20 bags of the same brand of candies was selected and found a mean weight of 120 grams. Assume that the population distribution of bag weights is normal. The weight of each bag was then recorded. The population standard deviation is known to be 2.1 grams. Construct a 90% confidence interval for the population mean weight of the candies. 3. A survey of 200 Internet users shows that they spend an average of 2 hours and 22 minutes per day on social networking. If the margin of error is 2.2 hours at 95% confidence, construct the confidence interval. 4. Suppose that a government law office does a study to determine the time needed to complete one personal profile sheet for consultation. It randomly surveys 100 people. The sample mean is 23.6 minutes. There is a known standard deviation of 7.0 minutes. The population distribution is assumed to be normal. Construct a 95% confidence interval for the population mean to complete the form. 5. A camp counselor is interested…Find the sample size need to find the Population Proportion if the margin of error is 4%, the confidence level is 99%, and the sample proportion is .41.
- Find r for a 0.99 confidence level when the sample size is 4You measure 33 textbooks' weights, and find they have a mean weight of 62 ounces. Assume the population standard deviation is 4.6 ounces. Based on this, construct a 95% confidence interval for the true population mean textbook weightIf X=101, o=27, and n= 32, construct a 95% confidence interval estimate of the population mean, p
- If n=200 and X=70, construct a 99% confidence interval estimate for the population proportion. SAS (Round to four decimal places as needed.)The estimated prevalence is 25% and the desired confidence is 95% with a margin of error of 4%. What is n=If x=76 ₁² = 14 and n=65, Construct a 95% Confidence interval estimate of the population mean, pe الكيك