A woman decides to have children until she has her first girl or until she has four children, whichever comes first. Let X = number of children she has. For simplicity, assume that the probability of a girlis .5 for each birth.(a) The simple events in the simple space are {G, BG, BBG, BBBG, BBBB}, where we use B for boy and G for girl. For instance, one simple event is BG, because the woman quits once she hasa girl. Find the probability for each of the simple events in the sample space.P(G) =P(BG) =P(BBG)P(BBBG) =P(BBBB)=(b) Find the probability distribution function for X.kP(X = k)1234

The objective of the question is to find the probability of each simple event in the sample space…

Answered: A woman decides to have children until…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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6. The age distribution of the members of a cer- tain children's club is as follows: Age on last birthday (in years) Frequency 5 9. 6. 18 7. 35 42 9. 32 10 15 11 12 3 There is a member A such that there are twice as many members older than A as there are younger than A. Estimate his age (in years up to two places of decimals).
A bag contains 10 Blue balls, 10 Red balls, and 9 Green balls. Two balls are going to be drawn from the bag (one at a time) and then put to the side (they are not returned to the bag). Let event B blue ball chosen, R = Red ball chosen, and G- Green ball chosen. What is the probability they are both red? What is P(R and R)? Write an answer to 4 decimal places.
Q1/a coin is flipped, and a die is rolled. Find the probability of getting a head on the coin and a number 4 on the die. Q2/1f the probability that will rain tomorrow is 0.20. What is the probability that will not rain tomorrow?
Q P.16: P(A and B) = 0. 32, P(not A and B) = 0.48. Find P(A) and P(B) if events A and B are independent.
Show all workings - use formulas: A group consists of 10 girls and 8 boys. A team of 9 are to be selected from this group. What is the probability that the team selected will consist of 5 girlsand 4 boys, but will not include ANY of 4 specific boys?
Trains arrive at the yard every 10 minutes and the service time is 20 minutes. If the line capacity of the yard is limited to 5 trains find: Probability that an arriving train will find an empty space in the yard
Let A and B be two events such that the probability of B is 0.5 and the probability of both is 0.2. Find the probability of A given that B occurs.
Q2/ An urn contains 5 red, 6 blue, and 8 green balls. If a set of 3 balls is randomly selected, what is the probability that each of the balls will be (a) of the same color? (b) of different colors? Ans: (a- 0.08875, b- 0.247)
The Addition Rule for the probability that events A or B or C will occur, P(A or B or C), is given by P(A or B or C)=P(A) + P(B) + P(C) - P(A and B)- P(A and C) - P(B and C) + P(A and B and C) Find P(A or B or C) for the given probabilities. P(A)=0.38, P(B) = 0.29, P(C) = 0.12 P(A and B)=0.12, P(A and C) = 0.04, P(B and C) = 0.06 P(A and B and C) = 0.01 P(A or B or C) =
A doctor gives a patient a 80% chance of surviving bypass surgery after a heart attack. If the patient survives the surgery, then the patient has a 40% chance that the heart damage will heal. Find the probability that the patient survives the surgery and the heart damage heals. The probability is (Type an integer or a decimal.)
The Addition Rule for the probability that events A or B or C will occur, P(A or B or C), is given by P(A or B or C)=P(A) + P(B) + P(C) - P(A and B)- P(A and C) - P(B and C) + P(A and B and C) Find P(A or B or C) for the given probabilities. P(A) = 0.32, P(B) = 0.24, P(C) = 0.11 P(A and B) = 0.13, P(A and C) = 0.03, P(B and C) = 0.08 P(A and B and C) = 0.01 P(A or B or C) = montesino P Pearson DELL S Hummert mana SEFERDESSERTS SIEMENS se fa m Next Copyright © 2022 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions Contac

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