A wire loop with a resistance, R = 0.160 Ohms is pulled to the right out of a %3D region with a uniform magnetic field B = 0.223 T that points out of the screen as shown in the diagram below. As is moves, out of the field region, a current is induced, because of the current, there is a magnetic force on the loop. How much force (magnitude only) is required to keep the loop moving at a constant speed of v = 10.0 m/s? The height of the loop, L = 0.394 m. %3D
A wire loop with a resistance, R = 0.160 Ohms is pulled to the right out of a %3D region with a uniform magnetic field B = 0.223 T that points out of the screen as shown in the diagram below. As is moves, out of the field region, a current is induced, because of the current, there is a magnetic force on the loop. How much force (magnitude only) is required to keep the loop moving at a constant speed of v = 10.0 m/s? The height of the loop, L = 0.394 m. %3D
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![A wire loop with a resistance, R = 0.160 Ohms is pulled to the right out of a
%3D
region with a uniform magnetic field B = 0.223 T that points out of the screen
as shown in the diagram below. As is moves, out of the field region, a current is
induced, because of the current, there is a magnetic force on the loop. How
much force (magnitude only) is required to keep the loop moving at a constant
speed of v = 10.0 m/s? The height of the loop, L = 0.394 m.
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7398fe87-36cb-4c43-878a-872d03c073c4%2F0ae7ada5-a609-41cf-8975-2bc3329ad210%2Fmb4wml.jpeg&w=3840&q=75)
Transcribed Image Text:A wire loop with a resistance, R = 0.160 Ohms is pulled to the right out of a
%3D
region with a uniform magnetic field B = 0.223 T that points out of the screen
as shown in the diagram below. As is moves, out of the field region, a current is
induced, because of the current, there is a magnetic force on the loop. How
much force (magnitude only) is required to keep the loop moving at a constant
speed of v = 10.0 m/s? The height of the loop, L = 0.394 m.
%3D
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