A window washer stands on a uniform plank of mass 125 kg and length 7m supported by a rope attached at the end of the plank at an angle of 30o. The window washer has a mass of 80.0 kg. What is the tension in the rope if the man stands 1.00 m from the left end of the plank?

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 A window washer stands on a uniform plank of mass 125 kg and length 7m supported by a rope attached at the end of the plank at an angle of 30o. The window washer has a mass of 80.0 kg. What is the tension in the rope if the man stands 1.00 m from the left end of the plank?

**Problem Statement:**

A window washer stands on a uniform plank of mass 125 kg and length 7 m supported by a rope attached at the end of the plank at an angle of 30°. The window washer has a mass of 80.0 kg. What is the tension in the rope if the man stands 1.00 m from the left end of the plank?

**Diagram Explanation:**
- The diagram depicts a man standing on a plank.
- The plank is inclined at an angle of 30 degrees from the horizontal, being held by a rope at one end.
- The man, representing the window washer, is standing 1.00 m from the left end of the plank.
- The rope labeled "T" indicates the tension force that is holding the plank at the angled position, originating from the mentioned angle of 30 degrees.

To solve this problem, use the principles of static equilibrium, where the sum of torques around any point should be zero, and the sum of forces both horizontally and vertically should also be zero.

**Key Data:**
- Mass of plank = 125 kg
- Length of plank = 7 meters
- Mass of window washer = 80 kg
- Distance from left end the man stands = 1 meter
- Angle of rope = 30°

Approaching this problem likely involves calculating the torque about the left end, considering the gravitational forces acting on the window washer and the plank, and the horizontal and vertical components of the tension in the rope. The typical analysis would require summing these forces and setting up equilibrium equations to solve for the unknown tension T in the rope.
Transcribed Image Text:**Problem Statement:** A window washer stands on a uniform plank of mass 125 kg and length 7 m supported by a rope attached at the end of the plank at an angle of 30°. The window washer has a mass of 80.0 kg. What is the tension in the rope if the man stands 1.00 m from the left end of the plank? **Diagram Explanation:** - The diagram depicts a man standing on a plank. - The plank is inclined at an angle of 30 degrees from the horizontal, being held by a rope at one end. - The man, representing the window washer, is standing 1.00 m from the left end of the plank. - The rope labeled "T" indicates the tension force that is holding the plank at the angled position, originating from the mentioned angle of 30 degrees. To solve this problem, use the principles of static equilibrium, where the sum of torques around any point should be zero, and the sum of forces both horizontally and vertically should also be zero. **Key Data:** - Mass of plank = 125 kg - Length of plank = 7 meters - Mass of window washer = 80 kg - Distance from left end the man stands = 1 meter - Angle of rope = 30° Approaching this problem likely involves calculating the torque about the left end, considering the gravitational forces acting on the window washer and the plank, and the horizontal and vertical components of the tension in the rope. The typical analysis would require summing these forces and setting up equilibrium equations to solve for the unknown tension T in the rope.
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