A wind turbine system has a double fed induction generator of 6 pole 50 Hz has the following parameters R1=0; R’2=10 mΩ, x1=x’2= 100 mΩ and the magnetizing reactance Xm=5 Ω. The effective turns ratio between ththe stator and rotor winding is 5. The terminal voltage is 690 V. Without injection, the machine is spinning at 1025 rpm. When the speed of the generator increases to 1050 rpm, a voltage of magnitude 5 V is injected in the rotor to keep the rotor current equal to 1 kA. Ignoring stator resistance, calculate the phase angle of the injected voltage.
A wind turbine system has a double fed induction generator of 6 pole 50 Hz has the following parameters R1=0; R’2=10 mΩ, x1=x’2= 100 mΩ and the magnetizing reactance Xm=5 Ω. The effective turns ratio between ththe stator and rotor winding is 5. The terminal voltage is 690 V. Without injection, the machine is spinning at 1025 rpm. When the speed of the generator increases to 1050 rpm, a voltage of magnitude 5 V is injected in the rotor to keep the rotor current equal to 1 kA. Ignoring stator resistance, calculate the phase angle of the injected voltage.
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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A wind turbine system has a double fed induction generator of 6 pole 50 Hz has the following parameters R1=0; R’2=10 mΩ, x1=x’2= 100 mΩ and the magnetizing reactance Xm=5 Ω. The effective turns ratio between ththe stator and rotor winding is 5. The terminal voltage is 690 V.
Without injection, the machine is spinning at 1025 rpm. When the speed of the generator increases to 1050 rpm, a voltage of magnitude 5 V is injected in the rotor to keep the rotor current equal to 1 kA. Ignoring stator resistance, calculate the phase angle of the injected voltage.
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