(a) Which antibacterial compound does NOT directly inhibit this process? H₂N NH cycloserine A Ph CO₂H penicillin G B OH NH₂ B-fluoro-L-alanine C H3C NH (b) Which statement about the "Park nucleotide" is correct? A. the N-acetylglucosamine ring is the L-enantiomer B. the diphosphate group at the anomeric center forms exclusively as the ß-anomer C. the five amino acids all have D configurations D. the anomeric center of the glucosamine ring has R configuration

Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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7. To prepare the "Park nucleotide", five amino acids must be attached to the lactide intermediate.
HO-
HO
ACHN O
OH
6969
lactide intermediate
O.
HO ÕH
_H
construct
pentapeptide
НО
HOO
CO₂H
H₂C
ACHNO.
N-H
HO₂C
Park nucleotide
j
H
(a) Which antibacterial compound does NOT directly inhibit this process?
H₂N
ad ex
NH
P
o'90'9
OH
H
NH₂
B-fluoro-L-alanine
0.
HO ÕH
H
NH₂
OH
NH₂
OH
H
H3C
cycloserine
penicillin G
B
A
(b) Which statement about the "Park nucleotide" is correct?
A. the N-acetylglucosamine ring is the L-enantiomer
B. the diphosphate group at the anomeric center forms exclusively as the ß-anomer
C. the five amino acids all have D configurations
D. the anomeric center of the glucosamine ring has R configuration
D
SCH3
H
Transcribed Image Text:7. To prepare the "Park nucleotide", five amino acids must be attached to the lactide intermediate. HO- HO ACHN O OH 6969 lactide intermediate O. HO ÕH _H construct pentapeptide НО HOO CO₂H H₂C ACHNO. N-H HO₂C Park nucleotide j H (a) Which antibacterial compound does NOT directly inhibit this process? H₂N ad ex NH P o'90'9 OH H NH₂ B-fluoro-L-alanine 0. HO ÕH H NH₂ OH NH₂ OH H H3C cycloserine penicillin G B A (b) Which statement about the "Park nucleotide" is correct? A. the N-acetylglucosamine ring is the L-enantiomer B. the diphosphate group at the anomeric center forms exclusively as the ß-anomer C. the five amino acids all have D configurations D. the anomeric center of the glucosamine ring has R configuration D SCH3 H
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