---**Statistical Analysis of Stay-at-Home Parents**In the past, 19% of all homes with a stay-at-home parent, the father is the stay-at-home parent. An independent research firm has been charged with conducting a sample survey to obtain more current information.### Questions:**(a)** What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.03? Use a 95% confidence level. (Round your answer up to the nearest whole number.)**(b)** Repeat part (a) using a 99% confidence level. (Round your answer up to the nearest whole number.)### Helpful Resources:- **Need Help?** - **Read it** - **Watch It** - **Master It**---(Note: There are no graphs or diagrams present in this image to explain.)

here given that margin of error = 0.03p = proportion of homes with the father stay at home parent =…

Answered: (a) What sample size is needed if the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A SURVEY WAS CONDUCTED IN 2010 AND 2020. THE 2010 RESULTS SUMMARIZED THE RESPONSES OF 1250 INDIVIDUALS, WHEREAS THE RESULTS OF THE 2020 SURVEY INVOLVED 1251 INDIVIDUALS. THE DATA ARE SUMMARIZED IN THE TABLE BELOW 1 HEALTH ISSUE ATE RECOMMENDED AMOUNT OF FIBROUS FOOD AVOIDED FAT 2010 SURVEY 2020 SURVEY 0.59 0.53 0.55 0.51 Construct a 95% confidence interval for the proportion of South Africans who avoided fat in 2010. Interpret your answer
You want to survey students to see what proportion of them have taken Statistics 101. This survey hasn't been previously completed, so no estimate is known. How large of a sample size is necessary if we want the margin of error to be within 4% with a 95% confidence interval?
How's the economy? A pollster wants to construct a 99.8% confidence interval for the proportion of adults who believe that economic conditions are getting better. (a) A poll taken in July 2010 estimates this proportion to be 0.29 . Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.03 ?
What is the best explanation or solution to the answer?
Treating the 2015 Tobacco rate data as a sample, construct a 95% confidence interval for the mean tobacco rate for males and for females. Interpret each interval. Does it appear that males use tobacco at a higher rate than females? Justify your answer, using the confidence intervals in your explanation. Construct the same confidence interval for males at the 99% confidence level. Compare to the male 95% confidence interval from the previous question. What happened to the interval when the confidence level increased? Explain why. Prevalence of smoking any tobacco product among persons aged >= 15 years Male 2015 Prevalence of smoking any tobacco product among persons aged >= 15 years Female 2015 51.2 7.6 37.2 27.8 29.5 18.4 52.3 1.5 16.7 13.1 35.5 34.8 46.5 0.4 48.8 7.6 39.8 0.7 13.1 0.9 46.2 10.6 26.5 20 17.7 1 30.5 17.1 47.2 30 19.3 11.3 29.3 3.1 42.4 28.2 36 4.5 22.2 3.5 44.1 2.8…
2.3 The width of a confidence interval is a measure of its precision. The narrower the confidence interval, the more precise is the interval estimate, and vice versa. Describe any three aspects that influence the precision of the width of a confidence interval of a single population mean.
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PROBLEM: A psychologist asks a random sample of 30 female adolescents and a separate, random sample of 30 male adolescents how much time they spend communicating with others online on an average day. She compares the time spent communicating online of female adolescents with that of male adolescents. In your project include: The problem and data. Calculate and interpret the correct 90% confidence interval for the mean difference in the two groups average time spent communicating online. (Use the 4 steps) Preform the correct significance test to test the claim that females spend more time than males communicating online. Use a level of significance of 0.05 and then use a level of significance of 0.10. Explain your results for each alpha. (Use the 4 steps) Answer the initial question and explain how you should use the confidence interval AND significance test to answer it. Review the rubric to make sure you include all necessary components. 1. Data: Hours…
Your statistics instructor claims that 60 percent of the students who take her Elementary Statistics class go through life feeling more enriched. For some reason that she can't quite figure out, most people don't believe her. You decide to check this out on your own. You randomly survey 64 of her past Elementary Statistics students and find that 34 feel more enriched as a result of her class. Construct a 95% confidence interval for the true mean or proportion. Round to the nearest hundredth (2 decimal places). ( , )
The percentage of Texans not covered by health care insurance in 2015 was 17%. The Texas Health and Human Services Commission (HHSC) has been charged with conducting a sample survey to obtain more current information. What sample size would you recommend if the HHSC’s goal is to estimate the current proportion of Texans without health care insurance with a margin of error of .03? Use a 95% confidence level. Repeat part (a) using a 99% confidence level.
Suppose you want to construct an 80% confidence interval for the proportion of businesses that provide incentives to their workers. Ifyou want a marginof error of 3.5%, how many business entities must you survey?
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