**DATAfile:** CorporateBondsYou may need to use the appropriate appendix table or technology to answer this question.A sample containing years to maturity and yield for 40 corporate bonds are contained in the file CorporateBonds. (Round your answers to four decimal places.)**Table 1**| Company Ticker | Years to Maturity | Yield ||----------------|-------------------|--------|| HSBC | 12.00 | 4.079 || GS | 9.75 | 5.367 || C | 4.75 | 3.332 || MS | 9.25 | 5.798 || C | 9.75 | 4.414 || TOTAL | 5.00 | 2.069 || MS | 5.00 | 4.739 || WFC | 10.00 | 3.682 || TOTAL | 10.00 | 3.270 || TOTAL | 3.25 | 1.748 || BAC | 9.75 | 4.949 || RABOBK | 9.75 | 4.203 || GS | 9.25 | 5.365 || AXP | 5.00 | 2.181 || MTNA | 5.00 | 4.366 || MTNA | 10.00 | 6.046 || JPM | 4.25 | 2.310 |**Table 2**| Company Ticker | Years to Maturity | Yield ||----------------|-------------------|--------|| FCX | 10.00 | 4.030 || GS | 25.50 | 6.913 || RABOBK | 4.75 | 2.805 || GE | 26.75 | 5.138 || HCN | 7.00 | 4.184 || GE | 9.50 | 3.778 || VOD | 5.00 | 1 The image shows data and questions related to corporate bonds. The data is presented in a table with columns indicating the issuer, years to maturity, and yield.**Table Overview:**| Issuer | Years to Maturity | Yield (%) ||--------|-------------------|----------|| JPM | 4.25 | 2.310 || GE | 26.00 | 5.130 || LNC | 10.00 | 4.163 || BAC | 5.00 | 3.699 || AIG | 5.00 | 3.452 || BAC | 29.75 | 5.903 || MS | 1.00 | 1.816 || T | 28.50 | 4.930 |**Questions:**(a) What is the sample mean years to maturity for corporate bonds and what is the sample standard deviation?$\bar{x} = \_\_\_\_\_$ yr$s = \_\_\_\_\_$ yr(b) Develop a 95% confidence interval for the population mean years to maturity.\[\_\_\_\_\_\] yr to \[\_\_\_\_\_\] yr(c) What is the sample mean yield on corporate bonds and what is the sample standard deviation?$\bar{x} = \_\_\_\_\_$ %$s = \_\_\_\_\_$ %(d) Develop a 95% confidence interval for the population mean yield on corporate bonds.\[\_\_\_\_\_\] % to \[\_\_\_\_\_\] %

Hey, since there are multiple subparts posted, we will answer first three subparts. If you want any specific subpart to be answered then please submit that subpart only or specify the subpart in your message. (a) Sample mean years to maturity for corporate bonds and its standard deviation: The sample mean years to maturity for corporate bonds can be calculated using EXCEL function as follows: Thus, x¯=9.71 yr The sample standard deviation of years to maturity for corporate bonds can be calculated using EXCEL function as follows: Thus, s=7.981 yr (b) 95% confidence interval for population mean years to maturity: Critical value: The two tailed t critical value at n-1=39 degrees of freedom and 95% confidence level is 2.0227. Calculation: The 95% confidence interval for population mean years to maturity can be calculated as follows: CI=x¯±tcsn=9.71±2.02277.98140=9.71±2.55246=7.158, 12.262(c) Sample mean yield for corporate bonds and its standard deviation: The sample mean yield for corporate bonds can be calculated using EXCEL function as follows: Thus, x¯=3.89 % The sample standard deviation of yield for corporate bonds can be calculated using EXCEL function as follows: Thus, s=1.619 %

Math

Statistics

(a) What is the sample mean years to maturity for corporate bonds and what is the sample standard deviation? X = yr yr = S (b) Develop a 95% confidence interval for the population mean years to maturity. yr to yr (c) What is the sample mean yield on corporate bonds and what is the sample standard deviation?

(a) What is the sample mean years to maturity for corporate bonds and what is the sample standard deviation? X = yr yr = S (b) Develop a 95% confidence interval for the population mean years to maturity. yr to yr (c) What is the sample mean yield on corporate bonds and what is the sample standard deviation?

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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