### Statistical Analysis of Corporate Bonds#### (a) Sample Mean Years to Maturity- **Question:** What is the sample mean years to maturity for corporate bonds and what is the sample standard deviation? - \( \bar{x} = \) _____ yr - \( s = \) _____ yr#### (b) Confidence Interval for Population Mean Years to Maturity- **Task:** Develop a 95% confidence interval for the population mean years to maturity. - _____ yr to _____ yr#### (c) Sample Mean Yield on Corporate Bonds- **Question:** What is the sample mean yield on corporate bonds and what is the sample standard deviation? - \( \bar{x} = \) _____ % - \( s = \) _____ %#### (d) Confidence Interval for Population Mean Yield- **Task:** Develop a 95% confidence interval for the population mean yield on corporate bonds. - _____ % to _____ % This exercise is designed to apply statistical methods to real-world financial scenarios, focusing on corporate bonds' maturity and yield analysis. **Corporate Bond Data**A sample containing years to maturity and yield for 40 corporate bonds are listed below. Each entry includes the company ticker, years to maturity, and yield. Note: Round your answers to four decimal places if needed.| Company Ticker | Years to Maturity | Yield ||----------------|-------------------|-------|| HSBC | 12.00 | 4.079 || GS | 9.75 | 5.367 || C | 4.75 | 3.332 || MS | 9.25 | 5.798 || C | 9.75 | 4.414 || TOTAL | 5.00 | 2.069 || MS | 5.00 | 4.739 || WFC | 10.00 | 3.682 || TOTAL | 10.00 | 3.270 || TOTAL | 3.25 | 1.748 || BAC | 9.75 | 4.949 || RABOBK | 9.75 | 4.203 || GS | 9.25 | 5.365 || AXP | 5.00 | 2.181 || MTNA | 5.00 | 4.366 || MTNA | 10.00 | 6.046 || JPM | 4.25 | 2.310 || GE | 26.00 | 5.130 || LNC | 10.00 | 4.163 || BAC | 5.00 | 3.699 || Company Ticker | Years to Maturity | Yield ||----------------|-------------------|-------|| FCX | 10.00 | 4.030 || GS | 25.50 | 6.913 || RABOBK | 4.75 | 2.805 || GE | 26.75 | 5.138 || HCN | 7.00 | 4.184 || GE | 9.50 | 3.778 || VOD | 5

As per honor code we can only provide answers to first three parts. a) Mean=∑xn=388.2540=9.70625…

(a) What is the sample mean years to maturity for corporate bonds and what is the sample standard deviation? X = yr S = yr (b) Develop a 95% confidence interval for the population mean years to maturity. yr to yr (c) What is the sample mean yield on corporate bonds and what is the sample standard deviation? X = % S = %

(a) What is the sample mean years to maturity for corporate bonds and what is the sample standard deviation? X = yr S = yr (b) Develop a 95% confidence interval for the population mean years to maturity. yr to yr (c) What is the sample mean yield on corporate bonds and what is the sample standard deviation? X = % S = %

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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