College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
Kindly provide the solution to the following question using the GRASS method:
A whale travels 25.0 km [E 30° N] and then moves 45.0 km [N 43.0° W]. What is the total displacement of the whale?
Image attached is a guide on how to use the GRASS method
![tiver:
Ad Ad
Required:
Ad Ad Ad
Y
Anclysis:
Let mooth & west be positive tv
4d² = Ad + Ad
2
Sektion:
N
(20.0km) (sin 25°)
(20.0xmXcos 25°)
(45.0 kyksin 40) X
WE
(45.0km) (cos 40.00)
40.0⁰
Ad Ad + Ad
Bd² = (-20.0kn) (co₁ 250) + (45.0 kn)(sin 40.0°)
bota
= 10.799 km
Ad = A + Act
Ady = (20.0 km.) (sin 250) + (45.0 kn X(cos 40.0")
Ady = [42.924 km]
| AZ²₂1 = √(40₂)² + (Ad4₂) ²
142, 1 =√ √/(10.799 kn)² + (42.924 kn)²
1Ad1=44.262 km
Scheton (contid):
-
O + tan" (Ads)
ở bán 42.921 km
-1
10.799 Kn
0 = 75.9°
Statene ti
Then fore, the displacement of
the whole is 4.43 x 10¹ kn [W76″N](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7b519efd-481f-44c9-b15a-1bd08236bdce%2F6c50d4f5-c27e-4169-9ced-815c83aea893%2Frrl9e8_processed.png&w=3840&q=75)
Transcribed Image Text:tiver:
Ad Ad
Required:
Ad Ad Ad
Y
Anclysis:
Let mooth & west be positive tv
4d² = Ad + Ad
2
Sektion:
N
(20.0km) (sin 25°)
(20.0xmXcos 25°)
(45.0 kyksin 40) X
WE
(45.0km) (cos 40.00)
40.0⁰
Ad Ad + Ad
Bd² = (-20.0kn) (co₁ 250) + (45.0 kn)(sin 40.0°)
bota
= 10.799 km
Ad = A + Act
Ady = (20.0 km.) (sin 250) + (45.0 kn X(cos 40.0")
Ady = [42.924 km]
| AZ²₂1 = √(40₂)² + (Ad4₂) ²
142, 1 =√ √/(10.799 kn)² + (42.924 kn)²
1Ad1=44.262 km
Scheton (contid):
-
O + tan" (Ads)
ở bán 42.921 km
-1
10.799 Kn
0 = 75.9°
Statene ti
Then fore, the displacement of
the whole is 4.43 x 10¹ kn [W76″N
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