Tutorial ExerciseA well-insulated electric water heater warms 116 kg of water from 20.0° C to 42.0° C in 24.0 min. Find theresistance of its heating element, which is connected across a 240-V potential difference.Part 1 of 5 - ConceptualizeWe expect the water heater to be high-powered compared to other household appliances. For the power to beon the order of kilowatts, the current would be several amperes and the resistance only a few ohms.Part 2 of 5 - CategorizeWe will find the energy required to heat the water. Then we will find the power of the heating element andcalculate its resistance from the power and the potential difference.Part 3 of 5 - AnalyzeWe know the mass of water m and the temperature change AT. The specific heat of water isC = 4 186 J/kg · °C. For the energy input by heat, we haveQ = mcATkg ) (4 186 J/kg · °C)x 10' J.SubmitSkip (you cannot come back)

water mass= 116 Kg time taken to heat water from 20C to 42C is 24 minutes.

Answered: A well-insulated electric water heater…

A well-insulated electric water heater warms 116 kg of water from 20.0° C to 42.0° C in 24.0 min. Find the resistance of its heating element, which is connected across a 240-V potential difference.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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