Tutorial ExerciseA well-insulated electric water heater warms 116 kg of water from 20.0° C to 42.0° C in 24.0 min. Find theresistance of its heating element, which is connected across a 240-V potential difference.Part 1 of 5 - ConceptualizeWe expect the water heater to be high-powered compared to other household appliances. For the power to beon the order of kilowatts, the current would be several amperes and the resistance only a few ohms.Part 2 of 5 - CategorizeWe will find the energy required to heat the water. Then we will find the power of the heating element andcalculate its resistance from the power and the potential difference.Part 3 of 5 - AnalyzeWe know the mass of water m and the temperature change AT. The specific heat of water isC = 4 186 J/kg · °C. For the energy input by heat, we haveQ = mcATkg ) (4 186 J/kg · °C)x 10' J.SubmitSkip (you cannot come back)

water mass= 116 Kg time taken to heat water from 20C to 42C is 24 minutes.

Answered: A well-insulated electric water heater…

A well-insulated electric water heater warms 116 kg of water from 20.0° C to 42.0° C in 24.0 min. Find the resistance of its heating element, which is connected across a 240-V potential difference.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Tutorial Exercise
A well-insulated electric water heater warms 116 kg of water from 20.0° C to 42.0° C in 24.0 min. Find the
resistance of its heating element, which is connected across a 240-V potential difference.
Part 1 of 5 - Conceptualize
We expect the water heater to be high-powered compared to other household appliances. For the power to be
on the order of kilowatts, the current would be several amperes and the resistance only a few ohms.
Part 2 of 5 - Categorize
We will find the energy required to heat the water. Then we will find the power of the heating element and
calculate its resistance from the power and the potential difference.
Part 3 of 5 - Analyze
We know the mass of water m and the temperature change AT. The specific heat of water is
C = 4 186 J/kg · °C. For the energy input by heat, we have
Q = mcAT
kg ) (4 186 J/kg · °C)
x 10' J.
Submit
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