(a) Weight of empty crucible 16-440 (b) Weight of crucible + magnesium 16-75215 (c) Weight of magnesium in crucible 0-312 9 (d) Weight of crucible after heating 16-954 9 0.517 9 И90 0.312 g Mg x I mol MaD. x (e) Weight of magnesium oxide present , ты ма 40.3049 mgo ·x 24-305 ама Imol Mg Imal Mgo absorbed by magnesium 0-5 mỗi bê ма ма (f) Weight of oxygen I mol Mg 0.2059 X X 1 -X.32 9 0₂- 1 mol 0₂ = 0·20590 Mg 24-305g (g) Moles of magnesium used 0.01284 0312 g Mg x 1 molimg. 24-305 = 0.01284 mol Mg gMg (h) Moles of oxygen 0-01284 Imol 0-312 9 mg x (i) Ratio of magnesium/oxygen Ratio Mg=0= (j) % error in experiment 16.7529-16.4409=0-312 9 0-312g Mg absorbed I mol Mg 24-3059 Mg mol Ma Mol 0 у Imol (1 mol 9 -0.517 g MgO mol Mg = 0·01284 mol Mg 3-417 0-9651 mol) /0.96516 mol xivo)=3-617-
(a) Weight of empty crucible 16-440 (b) Weight of crucible + magnesium 16-75215 (c) Weight of magnesium in crucible 0-312 9 (d) Weight of crucible after heating 16-954 9 0.517 9 И90 0.312 g Mg x I mol MaD. x (e) Weight of magnesium oxide present , ты ма 40.3049 mgo ·x 24-305 ама Imol Mg Imal Mgo absorbed by magnesium 0-5 mỗi bê ма ма (f) Weight of oxygen I mol Mg 0.2059 X X 1 -X.32 9 0₂- 1 mol 0₂ = 0·20590 Mg 24-305g (g) Moles of magnesium used 0.01284 0312 g Mg x 1 molimg. 24-305 = 0.01284 mol Mg gMg (h) Moles of oxygen 0-01284 Imol 0-312 9 mg x (i) Ratio of magnesium/oxygen Ratio Mg=0= (j) % error in experiment 16.7529-16.4409=0-312 9 0-312g Mg absorbed I mol Mg 24-3059 Mg mol Ma Mol 0 у Imol (1 mol 9 -0.517 g MgO mol Mg = 0·01284 mol Mg 3-417 0-9651 mol) /0.96516 mol xivo)=3-617-
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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i) What is the ratio of Magnesium/oxygen
j) What is the percent error in the experiment?
![### Experimental Data and Calculations: Oxidation of Magnesium
In this experiment, we aim to determine the empirical formula of magnesium oxide by oxidizing magnesium and subsequently measuring relevant masses.
#### Given Data and Calculations:
**(a) Weight of empty crucible:**
\[ 16.400 \, \text{g} \]
**(b) Weight of crucible + magnesium:**
\[ 16.752 \, \text{g} \]
**(c) Weight of magnesium in crucible:**
\[ \text{Calculated as} \]
\[ 16.752 \, \text{g} - 16.400 \, \text{g} = 0.352 \, \text{g} \]
**(d) Weight of crucible after heating:**
\[ 17.015 \, \text{g} \]
**(e) Weight of magnesium oxide present:**
\[ \text{Calculated as} \]
\[ 17.015 \, \text{g} - 16.400 \, \text{g} = 0.615 \, \text{g} \]
**(f) Weight of oxygen absorbed by magnesium:**
\[ \text{Calculated as} \]
\[ 0.615 \, \text{g} - 0.352 \, \text{g} = 0.263 \, \text{g} \]
#### Mole Calculations:
**(g) Moles of magnesium used:**
\[ \frac{0.352 \, \text{g}}{24.305 \, \text{g/mol}} = 0.01448 \, \text{mol} \]
**(h) Moles of oxygen absorbed:**
\[ \frac{0.263 \, \text{g}}{16.00 \, \text{g/mol}} = 0.01644 \, \text{mol} \]
#### Ratio Calculation:
**(i) Ratio of magnesium to oxygen:**
\[ \frac{0.01448 \, \text{mol Mg}}{0.01644 \, \text{mol O}} = 0.87962 \simeq 1.00 \]
#### Percent Error Calculation:
**(j) Percent error in experiment:**
\[ \text{% Error} = \frac{\lvert 0.87962 -](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F277ae00b-d056-42ed-a729-386f4fca5973%2F924d9977-58e1-4c54-8fd0-a2dc43e9867b%2Fqvd2iml_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Experimental Data and Calculations: Oxidation of Magnesium
In this experiment, we aim to determine the empirical formula of magnesium oxide by oxidizing magnesium and subsequently measuring relevant masses.
#### Given Data and Calculations:
**(a) Weight of empty crucible:**
\[ 16.400 \, \text{g} \]
**(b) Weight of crucible + magnesium:**
\[ 16.752 \, \text{g} \]
**(c) Weight of magnesium in crucible:**
\[ \text{Calculated as} \]
\[ 16.752 \, \text{g} - 16.400 \, \text{g} = 0.352 \, \text{g} \]
**(d) Weight of crucible after heating:**
\[ 17.015 \, \text{g} \]
**(e) Weight of magnesium oxide present:**
\[ \text{Calculated as} \]
\[ 17.015 \, \text{g} - 16.400 \, \text{g} = 0.615 \, \text{g} \]
**(f) Weight of oxygen absorbed by magnesium:**
\[ \text{Calculated as} \]
\[ 0.615 \, \text{g} - 0.352 \, \text{g} = 0.263 \, \text{g} \]
#### Mole Calculations:
**(g) Moles of magnesium used:**
\[ \frac{0.352 \, \text{g}}{24.305 \, \text{g/mol}} = 0.01448 \, \text{mol} \]
**(h) Moles of oxygen absorbed:**
\[ \frac{0.263 \, \text{g}}{16.00 \, \text{g/mol}} = 0.01644 \, \text{mol} \]
#### Ratio Calculation:
**(i) Ratio of magnesium to oxygen:**
\[ \frac{0.01448 \, \text{mol Mg}}{0.01644 \, \text{mol O}} = 0.87962 \simeq 1.00 \]
#### Percent Error Calculation:
**(j) Percent error in experiment:**
\[ \text{% Error} = \frac{\lvert 0.87962 -
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