A weight of 10 lb stretches a spring 6 inches. The weight is drawn 4 inches below its equilibrium position and given an initial velocity of 4in/sec. An identical spring has a different weight attached to it. This second weight is drawn down from its equilibrium position a distance equal to the amplitude of the first motion and then given an initial velocity of 3ft/sec. If the amplitude of the second motion is twice that of the first, what weight is attached to the second spring? The value of g is 32 ft/s².

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