Part AA weather balloon is inflated to a volume of 29.5 L at a pressure of 736 mmHg and a temperature of 27.6 °C. The balloon rises in the atmosphere to an altitude where the pressure is 400 mmHg and the temperature is -16.4 °C.Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude.\[ V_{\text{balloon}} = \] _________ L[Submit] [Request Answer][Provide Feedback]

The initial volume of the balloon = 29.5 LThe initial pressure of the balloon = 736 mmHgThe…

Answered: A weather balloon is inflated to a…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Part A

A weather balloon is inflated to a volume of 29.5 L at a pressure of 736 mmHg and a temperature of 27.6 °C. The balloon rises in the atmosphere to an altitude where the pressure is 400 mmHg and the temperature is -16.4 °C.

Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude.

\[ V_{\text{balloon}} = \] _________ L

[Submit] [Request Answer]

[Provide Feedback]

Expert Solution

Step 1: Consider the given information:

The initial volume of the balloon $open parentheses straight V subscript 1 close parentheses$ = 29.5 L

The initial pressure of the balloon $open parentheses straight P subscript 1 close parentheses$ = 736 mmHg

The initial temperature of the balloon $open parentheses straight T subscript 1 close parentheses equals 27.6 degree straight C equals 27.6 plus 273.15 equals 300.75 space straight K$

The final volume of the balloon $open parentheses straight V subscript 2 close parentheses$ = ?

The final pressure of the balloon $open parentheses straight P subscript 2 close parentheses$ = 400 mmHg

The final temperature of the balloon $open parentheses straight T subscript 2 close parentheses$ = $negative 16.4 space degree straight C equals negative 16.4 plus 273.15 equals 256.75 space straight K$

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