A water tank, in the shape of a cone, has water draining out, where its volume is changing at a rate of -0.25 ft³/sec. Find the rate at which the level of the water is changing when the level (h) is 10 feet. 12 V = 14 r²h Hint: If then r = 3h; Get V in terms of h only. 14 -0.25 ft³/sec dh = [?] ft/sec dt Round your answer to the nearest thousandth. Enter

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