A water molecule consists of an oxygen atom with two hydrogen atoms bound to it (figure). The angle between the two bonds is 106°. If the bonds are  r = 0.102 nm  long, where is the center of mass of the molecule? (Use a coordinate system centered in the oxygen atom, with the x axis to the right and the y axis upward.)

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Chapter1: Units, Trigonometry. And Vectors
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A water molecule consists of an oxygen atom with two hydrogen atoms bound to it (figure). The angle between the two bonds is 106°. If the bonds are 

r = 0.102 nm

 long, where is the center of mass of the molecule? (Use a coordinate system centered in the oxygen atom, with the x axis to the right and the y axis upward.)

 

The image illustrates the molecular geometry of a water (H₂O) molecule. It shows a central oxygen atom (O) connected to two hydrogen atoms (H) via single bonds. The bonds between the oxygen and hydrogen atoms are labeled with the variable "r," indicating bond length. The structure forms a bent shape with an angle of 53° between each hydrogen-oxygen bond and the vertical axis through the oxygen atom, resulting in a total H–O–H bond angle of 106°. This bent configuration is due to the electron pair repulsion in the oxygen atom, which influences the molecule's shape.
Transcribed Image Text:The image illustrates the molecular geometry of a water (H₂O) molecule. It shows a central oxygen atom (O) connected to two hydrogen atoms (H) via single bonds. The bonds between the oxygen and hydrogen atoms are labeled with the variable "r," indicating bond length. The structure forms a bent shape with an angle of 53° between each hydrogen-oxygen bond and the vertical axis through the oxygen atom, resulting in a total H–O–H bond angle of 106°. This bent configuration is due to the electron pair repulsion in the oxygen atom, which influences the molecule's shape.
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