A watch maker claims that the weekly error in their watches has standard deviation of 1 second. sample of 20 watches yields a sample standard deviation of significance level, do the data support the hypothesis that the standard deviation of the weekly error of the watches exceeds the 1 second claimed by the manufacturer? Formulate and carry ou s = 1.364 seconds. At the 1% the appropriate chi-square test. The null hypothesis is Ho . o = 1 0gnin include answers to a)-d) as in the previous hypothesis tests.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
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Chapter10: Statistics
Section: Chapter Questions
Problem 22SGR
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Please write a statement with a conclusion of the results. Thanks.
a) Ho: o=1
b1 df =
こ 20-1
こs9
New,
Gruen
hこzo id~4
and d -o.0L.
The
lower
cv)t cal
Vave is G844 aud the
Ui per Crideal Vawe is 38.58.
C) x? =
Cu-l)s?
こ(20-121.36
1
こ35.35
Transcribed Image Text:a) Ho: o=1 b1 df = こ 20-1 こs9 New, Gruen hこzo id~4 and d -o.0L. The lower cv)t cal Vave is G844 aud the Ui per Crideal Vawe is 38.58. C) x? = Cu-l)s? こ(20-121.36 1 こ35.35
A watch maker claims that the weekly error in their watches has standard deviation of 1 second. A
sample of 20 watches yields a sample standard deviation of
significance level, do the data support the hypothesis that the standard deviation of the weekly
error of the watches exceeds the 1 second claimed by the manufacturer? Formulate and carry out
s = 1.364 seconds. At the 1%
the appropriate chi-square test. The null hypothesis is
Ho .
o = 1
Again, include answers to a)-d) as in the previous hypothesis tests.
Transcribed Image Text:A watch maker claims that the weekly error in their watches has standard deviation of 1 second. A sample of 20 watches yields a sample standard deviation of significance level, do the data support the hypothesis that the standard deviation of the weekly error of the watches exceeds the 1 second claimed by the manufacturer? Formulate and carry out s = 1.364 seconds. At the 1% the appropriate chi-square test. The null hypothesis is Ho . o = 1 Again, include answers to a)-d) as in the previous hypothesis tests.
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