A W8 x 31 of A992 steel (Fy = 50 ksi) is used as a beam with lateral support at 5-foot intervals. Assume that C = 1.0 and compute the nominal flexural strength. For W8 x 31: = 9.19, Z, = 30.4 in.³, S₂ = 27.5 in.³, Lp = 7.18 ft. bf 2tf (Express your answer to three significant figures.) Mn = ft-kips
A W8 x 31 of A992 steel (Fy = 50 ksi) is used as a beam with lateral support at 5-foot intervals. Assume that C = 1.0 and compute the nominal flexural strength. For W8 x 31: = 9.19, Z, = 30.4 in.³, S₂ = 27.5 in.³, Lp = 7.18 ft. bf 2tf (Express your answer to three significant figures.) Mn = ft-kips
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
A W8 x 31 of A992 steel (Fy = 50 ksi) is used as a beam with lateral support at 5-foot intervals. Assume that C6 = 1.0 and compute the nominal flexural strength.
For W8 × 31: 2t
= 9.19. Zx = 30.4 in.3, Sx = 27.5 in.8, Lp = 7.18 ft.
![A W8 × 31 of A992 steel \((F_y = 50 \, \text{ksi})\) is used as a beam with lateral support at 5-foot intervals. Assume that \(C_b = 1.0\) and compute the nominal flexural strength.
For W8 × 31:
\[
\frac{b_f}{2t_f} = 9.19, \, Z_x = 30.4 \, \text{in}^3, \, S_x = 27.5 \, \text{in}^3, \, L_p = 7.18 \, \text{ft}.
\]
(Express your answer to three significant figures.)
\[
M_n = \underline{\hspace{2em}} \, \text{ft-kips}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F225ea937-ec91-4f60-983d-e6a97001b794%2Fa1d00ba8-7b27-4162-a73a-9ad095fbf170%2Ftlq12n_processed.png&w=3840&q=75)
Transcribed Image Text:A W8 × 31 of A992 steel \((F_y = 50 \, \text{ksi})\) is used as a beam with lateral support at 5-foot intervals. Assume that \(C_b = 1.0\) and compute the nominal flexural strength.
For W8 × 31:
\[
\frac{b_f}{2t_f} = 9.19, \, Z_x = 30.4 \, \text{in}^3, \, S_x = 27.5 \, \text{in}^3, \, L_p = 7.18 \, \text{ft}.
\]
(Express your answer to three significant figures.)
\[
M_n = \underline{\hspace{2em}} \, \text{ft-kips}
\]
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