A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 7 m long, fixed at the top and bottom, and has additional support in the weak direction 3 m from the top. Properties of the section are: A = 14,500 mm² , Ix = 258.6 x 10° mm“, I, = 84.375 x 10° mm* X 1. Calculate the critical slenderness ratio of the member. A. 26.208 С. 36.706 В. 45.882 D. 27.529 Calculate the nominal axial load capacity of the column. A. 3 104 kN C. 4 213 kN 2. B. 4 851 kN D.5 344 kN
A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 7 m long, fixed at the top and bottom, and has additional support in the weak direction 3 m from the top. Properties of the section are: A = 14,500 mm² , Ix = 258.6 x 10° mm“, I, = 84.375 x 10° mm* X 1. Calculate the critical slenderness ratio of the member. A. 26.208 С. 36.706 В. 45.882 D. 27.529 Calculate the nominal axial load capacity of the column. A. 3 104 kN C. 4 213 kN 2. B. 4 851 kN D.5 344 kN
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
15)
![NSCP 2015
Pn = FerAg
(505.3-1)
The flexural buckling stress, Fer, is determined as follows:
cr 5
KL
1. when
E
< 4.71
(or Fe 2 0.44F,)
r
Fy
Fer =
0.658Fe|
Fy
(505.3-2)
KL
E
> 4.71
( or F. < 0.44F,)
2. when
-
r
Fer = 0. 877F.
(505.3-3)
%3D
where
,= elastic critical buckling stress determined according
to Eq. 505.3-4, Section 505.4, or the provisions of
Section 503.2, as applicable, MPa.
e
Fe
(KL
(505.3-4)
(学)
2
A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression
member. It is 7 m long, fixed at the top and bottom, and has additional support in
the weak direction 3 m from the top. Properties of the section are: A = 14,500
mm² , Ix = 258.6 x 10° mm“,
I, = 84.375 x 106 mm4
1.
Calculate the critical slenderness ratio of the member.
В. 45.882
A. 26.208
С. 36.706
D. 27.529
Calculate the nominal axial load capacity of the column.
A. 3 104 kN
C. 4 213 kN
2.
B. 4 851 kN
D.5 344 kN
3.
Calculate the service axial dead load if the service axial live load is twice as
that of the dead load. Use LRFD.
В. 992 kN
D. 634 kN
A. 1 354 kN
C. 1 093 kN](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0d464c6f-099a-4727-9685-84a85709cd7a%2Fb71ae02c-7497-48cb-9f39-00cb4ec0b991%2Fty4uatn_processed.png&w=3840&q=75)
Transcribed Image Text:NSCP 2015
Pn = FerAg
(505.3-1)
The flexural buckling stress, Fer, is determined as follows:
cr 5
KL
1. when
E
< 4.71
(or Fe 2 0.44F,)
r
Fy
Fer =
0.658Fe|
Fy
(505.3-2)
KL
E
> 4.71
( or F. < 0.44F,)
2. when
-
r
Fer = 0. 877F.
(505.3-3)
%3D
where
,= elastic critical buckling stress determined according
to Eq. 505.3-4, Section 505.4, or the provisions of
Section 503.2, as applicable, MPa.
e
Fe
(KL
(505.3-4)
(学)
2
A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression
member. It is 7 m long, fixed at the top and bottom, and has additional support in
the weak direction 3 m from the top. Properties of the section are: A = 14,500
mm² , Ix = 258.6 x 10° mm“,
I, = 84.375 x 106 mm4
1.
Calculate the critical slenderness ratio of the member.
В. 45.882
A. 26.208
С. 36.706
D. 27.529
Calculate the nominal axial load capacity of the column.
A. 3 104 kN
C. 4 213 kN
2.
B. 4 851 kN
D.5 344 kN
3.
Calculate the service axial dead load if the service axial live load is twice as
that of the dead load. Use LRFD.
В. 992 kN
D. 634 kN
A. 1 354 kN
C. 1 093 kN
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