A W12x50 is used as a column to support an axial compressive load of 145kips. The length is 20feet, and the ends are pinned. Without regard to load or resistance factor, investigate this for stability. (The grade of steel need not be known: the critical buckling load is a function of the modulus of elasticity, not the yield stress or ultimate tensile stress). PROPERTIES OF W12X50: Ag = 14.6in^2, rx = 5.18in, ry = 1.96in, bf/2tf = 6.31, h/tw = 28.1, d = 12.2in, Ix = 391in^4, ly = 56.3in

A W12x50 is used as a column to support an axial compressive load of 145kips. The length is 20feet, and the ends are pinned. Without regard to load or resistance factor, investigate this for stability. (The grade of steel need not be known: the critical buckling load is a function of the modulus of elasticity, not the yield stress or ultimate tensile stress). PROPERTIES OF W12X50: Ag = 14.6in^2, rx = 5.18in, ry = 1.96in, bf/2tf = 6.31, h/tw = 28.1, d = 12.2in, Ix = 391in^4, ly = 56.3in

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

QI/ An aluminum bar carries the axial loads at the positions shown in Fig. 1, below. The diameter for part AB, BC and CD is 35 mm, 40 mm and 30 mm, respectively. The elastic modulus for aluminum is 72.4 x 10 N/mm. Determine the internal stresses at section (A-B), (B-C) and (C- D), and the elongation (AL) in length at each part of aluminum due to loading. в D 37 kN 10 kN 45 kN 18 kN 1000 mm 800 mm I 600 mm Fig. 1
Problem 1 An axial force of P is applied to the center of the rigid end plate shown below. If the portion of the load carried by the aluminum plates is half the portion of the load carried by the brass core, (a) determine the value of h, (b) the total load if the stress in the brass is 50 MPa. Brass core (E = 105 GPa) Aluminum plates (E = 70 GPa) Rigid end plate 300 mm 60 mim 40 mm
The column above is subjected to axial loading only. Assume the following: • E= 29000 ksi G = 10000 ksi • = 986 in4 A = 60 in? • L= 20 ft • Grade 60 steel (60 ksi yield stress) • The column is fixed at the top and pinned at the bottom Which of the following is closest to the maximum normal stress the column can support (before yielding or buckling)? 167 ksi 24 ksi 42 ksi 60 ksi
A 6.1 m long steel column is fixed at its base and pinned at the top end. The cross section is a W360×57. The steel has a yield strength oy = 250 MPa. a) Determine the critical load, Per b) What is the maximum column length to ensure failure due to yielding instead of buckling?
5. A bronze bar is fastened between a steel bar and an aluminum bar as shown in Figure 5. Axial loads are applied at the positions indicated. Find the largest value of P that will not exceed an overall deformation of 3.0 mm, or the following stresses: 140 MPa in the steel, 120 MPa in the bronze, and 80 MPa in the aluminum. Assume that the assembly is suitably braced to prevent buckling. Use Est = 200 GPa, Eal = 70 GPa, and Ebr = 83 GPa. Steel A = 480 mm² 1.0 m Bronze A = 650 mm² 3P 4P 2.0 m FIGURE 5 Aluminum A = 320 mm² 1.5 m 2P
The solid rod has a diameter of 20mm. Find the following: Angle of twist at C with respect to A (in radians) Angle of twist at B with respect to A (in radians) Maximum shear stress at A (in MPa) (Shear stress at support, at a point 7mm from center. (in MPa) A-36 steel with the following properties: Modulus of Elasticity, E = 29x10^3 ksi or 200 GPa Shear Modulus/Modulus of Rigidity, G = 11.5x10^3 ksi or 79.3 GPa Poisson's Ratio, nu = 0.260 Temperature Coefficient for thermal expansion, a = 6.6x10^-6/°F or 11.7x10^-6/°C
When designing a structural member, which of the following statements is FALSE? A. The allowable stress is used in calculating the maximum load to be applied. B. The ultimate stress depends on the Factor of Safety used. C. The ultimate stress is determined based on the material used. D. The allowable stress depends on how conservative the design is. Which of the following is NOT a valid reason for increasing the Factor of Safety? A. Higher uncertainty in loading conditions B. Higher design life C. Lower confidence in assumed/stated material properties D. Lower member importance Consider a 1,000-mm long, 25-mm diameter sample subjected to a tension test. Automatic high-precision gages recorded that for an applied load of 150 kN, the sample experienced a longitudinal strain of 2×10−3mm/mm. Assuming that the material remained elastic while loaded, determine its modulus of elasticity. A. 175.0 GPa B. 63.7 GPa C. 152.8 GPa D. 72.9 GPa
PROBLEM 1) An aluminum bar carries the axial loads at the positions shown. If E=70GPA, compute the total deformation of the bar. Assume that the bar is suitably braced to prevent buckling. 0.4m D 10KN 6) What is the deformation &c in mm? 0.8m 0.4m B 5KN 0.6m 20KN A=800 mm? A=1,200 mm²
Required information Consider the loading shown. The allowable normal stress for the steel used is 160 MPa. 0.8 m 50 kN/m B -2.4 m- 0.8 m For the selected design, determine the actual value of Om in the beam. (Round the final answer to one decimal place. You must provide an answer before moving to the next part.) The actual value of om in the beam is 160 MPa.
What is the manufacturing tensional yield strength (lbf) of grade S135 drill pipe? a. This is a trick question because drill pipe size is not provided b. The answer can’t be calculated because the length of the pipe is not given c. The yield strength is 135000 psi and is a property of the steel d. The yield strength is 135000 psi and depends on the cross-sectional area