A W 24 x 103 is used as a beam that is simply supported at its ends. The properties of the section is as follows: d=623.10 mm tw = 14.00 mm bf=228.60 mm tf = 24.90 mm A = 19,548.00 mm2 W = 153.76 kg/m Ix = 1,248,694,000,000 mm4 Sx = 4,008,005 mm3 rx = 252.74 mm ly = 49,532,000,000 mm4 Sy = 433,350.83 mm4 ry = 50.34 mm
A W 24 x 103 is used as a beam that is simply supported at its ends. The properties of the section is as follows: d=623.10 mm tw = 14.00 mm bf=228.60 mm tf = 24.90 mm A = 19,548.00 mm2 W = 153.76 kg/m Ix = 1,248,694,000,000 mm4 Sx = 4,008,005 mm3 rx = 252.74 mm ly = 49,532,000,000 mm4 Sy = 433,350.83 mm4 ry = 50.34 mm
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A W 24 x 103 is used as a beam that is simply supported at its ends. The properties of the section is as
follows:
d = 623.10 mm
tw = 14.00 mm
bf = 228.60 mm
tf = 24.90 mm
A = 19,548.00 mm2
W = 153.76 kg/m
rt = 59.18 mm
lx = 1,248,694,000,000 mm4
Sx = 4,008,005 mm3
rx = 252.74 mm
ly = 49,532,000,000 mm4
Sy = 433,350.83 mm4
ry = 50.34 mm

Transcribed Image Text:3. AW 610 x 153 is used as a beam that is simply supported at its ends. The properties of the
section is given in your copy. (Use 2015 NSCP) Its = 61 mm
The beam is laterally supported at supports only. Use Ex = 248 MPa.
a) Determine the allowable bending stress for a length of 2 m. (ASD & LRFD)
b) Determine the allowable bending stress for a length of 4 m. (ASD & LRFD)
c) Determine the allowable bending stress for a length of 9 m. (ASD & LRFD)
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