A W 10 x 45 is used as a beam with two lines of 19 mm diameter boplts in each flange using A 36 steel. There are at least three bolts in each line and the bolts are not staggered with respect to each other. Use LRFD Method.

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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Problem #1
A W 10 x 45 is used as a beam with two lines
of 19 mm diameter boplts in each flange using
A 36 steel. There are at least three bolts in
each line and the bolts are not staggered with
respect to each other. Use LRFD Method.
Prop. of W 10 x 45
A = 8581 mm?
d = 256.54 mm
bf = 203.71 mm
tr = 15.75 mm
tw = 8.89 mm
Fy = 248 MPa
Fu = 400 MPa
O Determine the effective net area that
can be assumed to resist tension of the
section through the holes.
Ae = U An
U = 0.90
® Determine the design strength due to
fracture in the net section where bolt or
rivet holes are present. ø = 0.75
® Determine the design strength due to
yielding in the gross section which is
prevented
member.
inteded
to
excessive
203.71 mm
elongation of t
0.90
I- 15.75 mm
d=256.64 mm
15.75 mm
Transcribed Image Text:Problem #1 A W 10 x 45 is used as a beam with two lines of 19 mm diameter boplts in each flange using A 36 steel. There are at least three bolts in each line and the bolts are not staggered with respect to each other. Use LRFD Method. Prop. of W 10 x 45 A = 8581 mm? d = 256.54 mm bf = 203.71 mm tr = 15.75 mm tw = 8.89 mm Fy = 248 MPa Fu = 400 MPa O Determine the effective net area that can be assumed to resist tension of the section through the holes. Ae = U An U = 0.90 ® Determine the design strength due to fracture in the net section where bolt or rivet holes are present. ø = 0.75 ® Determine the design strength due to yielding in the gross section which is prevented member. inteded to excessive 203.71 mm elongation of t 0.90 I- 15.75 mm d=256.64 mm 15.75 mm
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