**Physics Problem: Calculating Time and Acceleration***A VW Beetle goes from 0 to 48.0 mi/h with an acceleration of +2.35 m/s².***(a) How much time does it take for the Beetle to reach this speed?**To solve this, we use the equation of motion:\[ v = u + at \]Where:- \( v \) is the final velocity- \( u \) is the initial velocity (0 in this case)- \( a \) is the acceleration- \( t \) is the timeFirst, we need to convert 48.0 mi/h to m/s:\[ 48.0 \text{ mi/h} = 48.0 \times 0.44704 \text{ m/s} = 21.458 \text{ m/s} \]Now, substitute the values into the equation:\[ 21.458 = 0 + (2.35)t \]\[ t = \frac{21.458}{2.35} \]\[ t \approx 9.13 \text{ seconds} \]**(b) A top-fuel dragster can go from 0 to 48.0 mi/h in 0.800 s. Find the acceleration (in m/s²) of the dragster.**Using the same equation of motion:\[ v = u + at \]Convert 48.0 mi/h to m/s:\[ 48.0 \text{ mi/h} = 48.0 \times 0.44704 \text{ m/s} = 21.458 \text{ m/s} \]Substitute the values into the equation:\[ 21.458 = 0 + a(0.800) \]\[ a = \frac{21.458}{0.800} \]\[ a \approx 26.82 \text{ m/s²} \]This problem illustrates the principles of linear motion and the importance of unit conversion in solving physics problems.

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A VW Beetle goes from 0 to 48.0 mi/h with an acceleration of +2.35 m/s². (a) How much time does it take for the Beetle to reach this speed? (b) A top-fuel dragster can go from 0 to 48.0 mi/h in 0.800 s. Find the acceleration (in m/s²) of the dragster.

A VW Beetle goes from 0 to 48.0 mi/h with an acceleration of +2.35 m/s². (a) How much time does it take for the Beetle to reach this speed? (b) A top-fuel dragster can go from 0 to 48.0 mi/h in 0.800 s. Find the acceleration (in m/s²) of the dragster.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

**Physics Problem: Calculating Time and Acceleration**

*A VW Beetle goes from 0 to 48.0 mi/h with an acceleration of +2.35 m/s².*

**(a) How much time does it take for the Beetle to reach this speed?**

To solve this, we use the equation of motion:
\[ v = u + at \]

Where:
- \( v \) is the final velocity
- \( u \) is the initial velocity (0 in this case)
- \( a \) is the acceleration
- \( t \) is the time

First, we need to convert 48.0 mi/h to m/s:
\[ 48.0 \text{ mi/h} = 48.0 \times 0.44704 \text{ m/s} = 21.458 \text{ m/s} \]

Now, substitute the values into the equation:
\[ 21.458 = 0 + (2.35)t \]
\[ t = \frac{21.458}{2.35} \]
\[ t \approx 9.13 \text{ seconds} \]

**(b) A top-fuel dragster can go from 0 to 48.0 mi/h in 0.800 s. Find the acceleration (in m/s²) of the dragster.**

Using the same equation of motion:
\[ v = u + at \]

Convert 48.0 mi/h to m/s:
\[ 48.0 \text{ mi/h} = 48.0 \times 0.44704 \text{ m/s} = 21.458 \text{ m/s} \]

Substitute the values into the equation:
\[ 21.458 = 0 + a(0.800) \]
\[ a = \frac{21.458}{0.800} \]
\[ a \approx 26.82 \text{ m/s²} \]

This problem illustrates the principles of linear motion and the importance of unit conversion in solving physics problems.

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