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A voltage waveform e(t) is described as follows, for the first half-cycle: e(t) = 60 volts at t = 0 sec., Increases linearly to 100 volts at t=0.005 sec., Decreases linearly to 60 volts at t=0.01 sec. Determine the root-mean-square or RMS value of this voltage, noting that, at least for a half- cycle, the RMS procedure involves squaring the voltage, taking the mean of the square, and taking the square root of the mean.

A voltage waveform e(t) is described as follows, for the first half-cycle: e(t) = 60 volts at t = 0 sec., Increases linearly to 100 volts at t=0.005 sec., Decreases linearly to 60 volts at t=0.01 sec. Determine the root-mean-square or RMS value of this voltage, noting that, at least for a half- cycle, the RMS procedure involves squaring the voltage, taking the mean of the square, and taking the square root of the mean.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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4. A voltage waveform e(t) is described as follows, for the first half-cycle: e(t) = 60 volts at t = 0 sec., %3! Increases linearly to 100 volts at t=0.005 sec., Decreases linearly to 60 volts at t=0.01 sec. Determine the root-mean-square or RMS value of this voltage, noting that, at least for a half- cycle, the RMS procedure involves squaring the voltage, taking the mean of the square, and taking the square root of the mean.
Transcribed Image Text:4. A voltage waveform e(t) is described as follows, for the first half-cycle: e(t) = 60 volts at t = 0 sec., %3! Increases linearly to 100 volts at t=0.005 sec., Decreases linearly to 60 volts at t=0.01 sec. Determine the root-mean-square or RMS value of this voltage, noting that, at least for a half- cycle, the RMS procedure involves squaring the voltage, taking the mean of the square, and taking the square root of the mean.
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