A volleyball is hit when it is 4 ft above the ground and 12 ft from a 6-ft-high net. It leaves the point of impact with an initial velocity of 35 ft/sec at an angle of 33° and slips by the opposing team untouched. The acceleration due to gravity is g= 32 ftisec. Answer the following questions. a. Find a vector form for the path of the volleyball. (Do not evaluate. Do not include the degree symbol in your answer.)

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Motion In Two Dimensions
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A volleyball is hit when it is 4 ft above the ground and 12 ft from a 6-ft-high net. It leaves the point of impact with an initial velocity of 35 ft/sec at an angle of 33° and slips by the opposing team untouched. The acceleration due to gravity is g= 32 ft/sec. Answer the following questions.
a. Find a vector form for the path of the volleyball.
r(t) =i+i
(Do not evaluate. Do not include the degree symbol in your answer.)
Transcribed Image Text:A volleyball is hit when it is 4 ft above the ground and 12 ft from a 6-ft-high net. It leaves the point of impact with an initial velocity of 35 ft/sec at an angle of 33° and slips by the opposing team untouched. The acceleration due to gravity is g= 32 ft/sec. Answer the following questions. a. Find a vector form for the path of the volleyball. r(t) =i+i (Do not evaluate. Do not include the degree symbol in your answer.)
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