A very small effect size can turn out to be statistically significant because the assumptions underlying the z test were too strict population standard deviations were too large deviation scores were used rather than raw scores the sample size was very large
Q: Polokwane butchery supplies Vienna sausages in the entire of Kzn province. An inspector from the…
A: From the provided information, Population variance (σ2) = 0.49 Standard deviation (σ) = 0.7…
Q: A sample of colored candies was obtained to determine the weights of different colors. The ANOVA…
A: Decision rule: If P-value≤α, then reject the null hypothesis. Otherwise, do not reject the null…
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A: Test statistic = 2.63, significance level = 0.01.
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A: We know that if the chi-square value is large than the critical value then it will not fit the…
Q: If you have a sample size of 100 from a population of rope with sample mean breaking strength of 960…
A: Solution: Let X be the breaking strength. From the given information, x-bar = 960 pounds, S=200…
Q: A pooled variance estimate is useful for two-sample hypothesis tests of a normal mean when the…
A: It is given that the population variances are equal.
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Q: How many packs should the inspector sample in order to be 99% confident that the sample mean will…
A: Given : Margin of error=E=0.2 kg Population standard deviation=σ2=0.49 kg Significance level=α=0.01…
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A: Hey there! Thank you for posting the question. Since your question has more than 3 parts, we are…
Q: Should be consider this score unusual? What is the value of the test statistic?
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A: Given: x¯1=110n1=10s12=200x¯2=100n2=15s22=150 Hypothesis: The null and alternative hypotheses are…
Q: A sample of colored candies was obtained to determine the weights of different colors. The ANOVA…
A: From the given information, level of significance is 0.025. The hypotheses is Null hypothesis: The…
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Q: Polokwane Butchery supplies Vienna sausages in the entire of KZN province. An Inspector from the…
A: Determine the number of packs that need to be sampled. The number of packs that needs to be sampled…
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A: One sided approach: The test hypotheses are: Null hypothesis: H0: μ = 6. Alternative hypothesis: H1:…
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A: Given statement If a sample is an extreme result and is significant, it will fall in the critical…
Q: Polokwane Butchery supplies Vienna sausages in the entire of KZN province. An Inspector fromthe CCSA…
A: Solution: From the given information, confidence level is 0.99, σ2=0.49 and E=0.2.
Q: A pooled variance estimate is useful for two-sample hypothesis tests of a normal mean when the…
A: Solution: The given statement is “A pooled variance estimate is useful for two-sample hypothesis…
Q: Polokwane Butchery supplies Vienna sausages in the entire of KZN province. An inspector from the…
A: Given information: Sample mean will differ by at most 0.2 kg. That means, Margin of error is:
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A: Solution: Here, the hypothesis test is to be conducted if the average IQ of employees at high-tech…
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Q: Give one method to increase statistical power and Which test statistic should you use if you are…
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Q: If the variance of Aeronautical Engineering board examination results is 144, what is the minimum…
A: Answer - If the variance of Aeronautical Engineering board examination results is σ2 = 144, what is…
Q: There are many ways to measure the reading ability of children. One frequently used test is the DRP…
A: Given: μ=32x¯=35.2σ=11n=41 Hypothesis: The null and alternate hypotheses are below: H0: μ=32H1:…
Q: the homogeneity of variances assumption states that the variance in the two samples must be equal?…
A: Homogeneity of variances always make about the population variance not about sample.
Q: A type 2 error occurs when a treatment actually does have an effect on the scores but the effect was…
A: True. we know that, type 2 error occurs when we fail to reject Null hypothesis when it is actually…
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- Using paired (dependent) observations is most advantageous for rejecting null hypotheses when the correlation between the X and Y scores is high standard deviations must be estimated from samples sample size is unequal the correlation between the X and Y scores is low OO0 0Given that the researcher wants to be sure the mean difference in the change in hemoglobin levels has a margin of error no more than 0.2 g/dL and the difference in the stand deviation between the mean hemoglobin levels for the two forms of iron supplements used to treat anemia is 1.2 g/dL, what is the desired number of recruits for the study, assuming the individuals will participate in a crossover trial, if the study’s attrition rate is expected to be .25? Group of answer choices n = 139 n = 554 n = 185 n = 55,320Given that the researcher wants to be sure the mean difference in the change in hemoglobin levels has a margin of error no more than 0.2 g/dL and the difference in the stand deviation between the mean hemoglobin levels for the two forms of iron supplements used to treat anemia is 1.2 g/dL, what is the desired number of recruits for the study, assuming the individuals will participate in a crossover trial, if the study’s attrition rate is expected to be .25? n= 139 n= 186 n= 554 n= 55,320
- What would an H0 (Null) look like for an ANOVA? At least one of the sample means is different from another mean There is a direct relationship between two of the sample means There are no differences between any of the sample means All of the sample means are different from each otherIn a study of 110 women and 116 men, it was found that mean body temperature for women was 97.690 F and mean body temperature for men was 97.450 F. Assume that the populations are independent, and the standard deviations were found to to be 0.89o F for women, and 0.660 F for men. Use an α = 0.05 significance level to test the claim that woman and men have different mean body temperatures. For full credit your hypothesis test must include: the claim, the null and alternate hypothesis, your test statistic and corresponding p-value, your decision, and the interpretation of your decision as it relates to the claim. It is acceptable to use technology to calculate the test statistic and the p-value here.A sample of colored candies was obtained to determine the weights of different colors. The ANOVA table is shown below. It is known that the population distributions are approximately normal and the variances do not differ greatly. Use a 0.025 significance level to test the claim that the mean weight of different colored candies is the same. If the candy maker wants the different color populations to have the same mean weight, do these results suggest that the company has a problem requiring IS corrective action? Source: DF: s: MS: Test Stat, F: Critical F: P-Value: 0.6049 0.001 0.001 Treatment: 5 0.005 2.7361 0.6963 Error: 77 0.077 Total: 82 0.082 Should the null hypothesis that all the colors have the same mean weight be rejected? O A. No, because the P-value is greater than the significance level. or B. Yes, because the P-value is greater than the significance level. O C. No, because the P-value is less than the significance level. O D. Yes, because the P-value is less than the…
- The national average for the number of students per teacher for all U.S. public schools in 15.9 Arandom sample of 12 school districts from a moderately populated area showed that the mean number of students per teacher was 19.2 with a variance of 4.41. Estimate the true mean number of students per teacher with 95% confidence. How does your estimate compare with the national average?Professor Smith took a sample of 210 students from her morning class and a sample of 163 students from her evening class. On Exam 1, all those sampled from the morning class got a 67 while those sampled from the evening class averaged a 67 with a variance of 127. If Professor Smith combines these two samples.What is the combined Exam 1 Average?What is the combined Exam 1 median?What is the combined Exam 1 Standard Deviation?A bank wants to determine whether a customer's preference for using cash or credit can be used to predict whether they will answer the phone on a weekday evening. What would be the most appropriate procedure to use to analyze data to answer this question? Only choose a test that handles multiple comparisons If such a test is needed. Regression Test of Slope or Correlation O Test for a Difference of Proportions O Test for a Difference of Means O Chi-square test of association O ANOVA (Analysis of Variance)
- The variability of oil prices per barrel has been very stable for the past 26 weeks. You would like to see if the variability of gas prices in San Diego has changed. The standard deviation of gas prices during periods of such stability has been 30 cents and it was thought that these prices were relatively normally distributed. You would like to see if they have changed so you randomly select 26 gas prices from this time period and get a sample standard deviation is 37.5 cents. At the level of significance of .05 see if gas prices variability has changed. Do the 5 step process to conduct a hypothesis test. Also at what critical value would you reject the null hypothesis?please show work, really need it to study!! thank you!!A study was made of a sample of 25 records of patients seen at a chronic disease hospital on an outpatient basis. The mean number of outpatient visits per patient was 4.8, and the sample standard deviation was 2. Can it be concluded from these data that the population mean is greater than four visits per patient?