A very simply supported beam is 5 feet long and has a large weight sitting at the center. The sag of the beam at its center (the difference between the bottom most point of the beam and the top of the supports) is 10 inches. Assuming that the shape of the beam is parabolic, find an equation of the parabola. x² = 5y x = 90y x² = 90y x = 90y² ► ✰

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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1 89°F
Partly sunny
1
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Q
A very simply supported beam is 5 feet long and has a large weight sitting at the center. The sag of the beam at
its center (the difference between the bottom most point of the beam and the top of the supports) is 10 inches.
Assuming that the shape of the beam is parabolic, find an equation of the parabola.
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x² = 5y
x = 90y
x² = 90y
x = 90y²
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Transcribed Image Text:1 89°F Partly sunny 1 F1 Q A very simply supported beam is 5 feet long and has a large weight sitting at the center. The sag of the beam at its center (the difference between the bottom most point of the beam and the top of the supports) is 10 inches. Assuming that the shape of the beam is parabolic, find an equation of the parabola. O F2 2 W x² = 5y x = 90y x² = 90y x = 90y² F3 #M 3 E C F4 $ 4 R F5 F % 5 Q Search F6 T G * 6 F7 4- Y H F8 & 7 + U F9 со ж 8 Ci F10 Lå K GO F11 0 F12 P Prt Sc + 11 [ Insert Del Backspace Enter 12:09 PM 6/30/2023 ➤ * * 7 Home
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