A vertically oriented square loop of copper wire falls from Substituting the expressions for FB and m into second Newton's Law. rest in a region in which the field B is horizontal, uniform, and perpendicular to the plane of the loop, into a field- free region, see (Figure 1). The side length of the loop is s and the wire diameter is d. The resistivity of copper is PR and the density of copper is pm. If the loop reaches its terminal speed while its upper segment is still in the magnetic-field region, find an expression for the terminal speed. FB = mg Bs²v = Pm STd²g B² sv, nd? 16pR = Pm 8Tdg 16PRPM9 EVALUATE Part O How does the terminal speed depend on the magnetic-field magnitude B? • View Available Hint(s) Figure < 1 of 1 O vy ~ B
A vertically oriented square loop of copper wire falls from Substituting the expressions for FB and m into second Newton's Law. rest in a region in which the field B is horizontal, uniform, and perpendicular to the plane of the loop, into a field- free region, see (Figure 1). The side length of the loop is s and the wire diameter is d. The resistivity of copper is PR and the density of copper is pm. If the loop reaches its terminal speed while its upper segment is still in the magnetic-field region, find an expression for the terminal speed. FB = mg Bs²v = Pm STd²g B² sv, nd? 16pR = Pm 8Tdg 16PRPM9 EVALUATE Part O How does the terminal speed depend on the magnetic-field magnitude B? • View Available Hint(s) Figure < 1 of 1 O vy ~ B
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Chapter1: Units, Trigonometry. And Vectors
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![I Review I Constants
A vertically oriented square loop of copper wire falls from
rest in a region in which the field B is horizontal, uniform,
and perpendicular to the plane of the loop, into a field-
free region, see (Figure 1). The side length of the loop is
s and the wire diameter is d. The resistivity of copper is
PR and the density of copper is Pm. If the loop reaches
its terminal speed while its upper segment is still in the
magnetic-field region, find an expression for the terminal
speed.
Substituting the expressions for FB and m into second Newton's Law.
Fв
= mg
R
= Pm8Td²g
B²sv,Td?
16PR
= Pm STd²g
16PRPM9
Ut
EVALUATE
Part O
How does the terminal speed depend on the magnetic-field magnitude B?
• View Available Hint(s)
Figure
1 of 1
O Ut ~
Square loop of
copper wire
ks = side length
X X X
O The terminal speed does not depend on the magnetic-field magnitude
X x x xBx x
Above this line:
B uniform and horizontal
s = side
length
- 1/B
O vt ~
O vt ~
- 1/(B²)
Below this line:
B = 0
d = wire diameter
Submit
Ucerminal](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5c8d8639-4d29-4712-9069-b7b0d8ad1876%2Ff532a296-8f12-4c1c-bc58-8887747517ce%2F6gvc1p_processed.png&w=3840&q=75)
Transcribed Image Text:I Review I Constants
A vertically oriented square loop of copper wire falls from
rest in a region in which the field B is horizontal, uniform,
and perpendicular to the plane of the loop, into a field-
free region, see (Figure 1). The side length of the loop is
s and the wire diameter is d. The resistivity of copper is
PR and the density of copper is Pm. If the loop reaches
its terminal speed while its upper segment is still in the
magnetic-field region, find an expression for the terminal
speed.
Substituting the expressions for FB and m into second Newton's Law.
Fв
= mg
R
= Pm8Td²g
B²sv,Td?
16PR
= Pm STd²g
16PRPM9
Ut
EVALUATE
Part O
How does the terminal speed depend on the magnetic-field magnitude B?
• View Available Hint(s)
Figure
1 of 1
O Ut ~
Square loop of
copper wire
ks = side length
X X X
O The terminal speed does not depend on the magnetic-field magnitude
X x x xBx x
Above this line:
B uniform and horizontal
s = side
length
- 1/B
O vt ~
O vt ~
- 1/(B²)
Below this line:
B = 0
d = wire diameter
Submit
Ucerminal
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