A vertically oriented square loop of copper wire falls from rest in a region in which the field B is horizontal, uniform, and perpendicular to the plane of the loop, into a field- free region, see (Figure 1). The side length of the loop is s and the wire diameter is d. The resistivity of copper is PR and the density of copper is pm . If the loop reaches its terminal speed while its upper segment is still in the magnetic-field region, find an expression for the terminal speed. v Correct The magnetic force is determined as the product of the current, length and the magnitude of the perpendicular component of the magnetic field, FB = ILB. Substituting the result of the previous part gives FB = Part L Find the resistance R of the loop. Express your answer in terms of the variables s, d, and pR. • View Available Hint(s) ΠνΠ ΑΣφ ? Figure 1 of 1 R = Square loop of copper wire x ks = side length Submit ---- Above this line: B uniform and horizontal s = side Part M Complete previous part(s) length Below this line: B = 0 | = wire diameter Part N Complete previous part(s) Ueerminal = ? EVALUATE
A vertically oriented square loop of copper wire falls from rest in a region in which the field B is horizontal, uniform, and perpendicular to the plane of the loop, into a field- free region, see (Figure 1). The side length of the loop is s and the wire diameter is d. The resistivity of copper is PR and the density of copper is pm . If the loop reaches its terminal speed while its upper segment is still in the magnetic-field region, find an expression for the terminal speed. v Correct The magnetic force is determined as the product of the current, length and the magnitude of the perpendicular component of the magnetic field, FB = ILB. Substituting the result of the previous part gives FB = Part L Find the resistance R of the loop. Express your answer in terms of the variables s, d, and pR. • View Available Hint(s) ΠνΠ ΑΣφ ? Figure 1 of 1 R = Square loop of copper wire x ks = side length Submit ---- Above this line: B uniform and horizontal s = side Part M Complete previous part(s) length Below this line: B = 0 | = wire diameter Part N Complete previous part(s) Ueerminal = ? EVALUATE
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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
Transcribed Image Text:I Review I Constants
A vertically oriented square loop of copper wire falls from
rest in a region in which the field B is horizontal, uniform,
and perpendicular to the plane of the loop, into a field-
free region, see (Figure 1). The side length of the loop is
s and the wire diameter is d. The resistivity of copper is
PR and the density of copper is Pm. If the loop reaches
its terminal speed while its upper segment is still in the
magnetic-field region, find an expression for the terminal
speed.
Correct
The magnetic force is determined as the product of the current, length and the magnitude of the
perpendicular component of the magnetic field, FB = ILB. Substituting the result of the previous part
B² s² vt
gives FB
R
Part L
Find the resistance R of the loop.
Express your answer in terms of the variables s, d, and PR.
• View Available Hint(s)
ΑΣφ
Figure
1 of 1
R =
ks = side length
Square loop of
copper wire ..X
Submit
X x x xB x x
Above this line:
B uniform and horizontal
s = side
length
Part M Complete previous part(s)
Below this line:
B = 0
d = wire diameter
Part N Complete previous part(s)
Verminal = ?
EVALUATE
Part O Complete previous part(s)
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