**Title: Understanding Oscillation in a Spring-Block System**A vertical spring has a 0.463-kg block hung from it, and you wait till the spring comes to rest at reaches an equilibrium. The spring is now 0.694 meters longer.**What is the spring constant of the spring?**- **Spring constant:** [Input box] N/mYou gently pull the block down an additional 0.346 m and hold the block at rest. Then releasing the block, and assuming no damping, what is the period of oscillation of the block–spring system?- **Period of oscillation:** [Input box] sHow high above the point of release does the block reach as it oscillates?- **Height:** 0.694 m

Solution:-Given thatmass of block (m)=0.463 kgspring deflection (x)=0.694 m

A vertical spring has a 0.463-kg block hung from it, and you wait till the spring comes to rest at reaches an equilibrium. The spring is now 0.694 meters longer. What is the spring constant of the spring? spring constant: N/m You gently pull the block down an additional 0.346 m and hold the block at rest. Then releasing the block, and assuming no damping, what is the period of oscillation of the block-spring system? period of oscillation: How high above the point of release does the block reach as it oscillates? height: .694

A vertical spring has a 0.463-kg block hung from it, and you wait till the spring comes to rest at reaches an equilibrium. The spring is now 0.694 meters longer. What is the spring constant of the spring? spring constant: N/m You gently pull the block down an additional 0.346 m and hold the block at rest. Then releasing the block, and assuming no damping, what is the period of oscillation of the block-spring system? period of oscillation: How high above the point of release does the block reach as it oscillates? height: .694