A vertical solid steel post of diameter d = 26 cm and length L = 2.70 m is required to support a load of mass m = 8400 kg. You can ignore the weight of the post. What is the stress in the post? Express your answer in pascals. What is the strain in the post?
Q: An 9.63-kg stone at the end of a steel (Young's modulus 2.0 x 1011 N/m²) wire is being whirled in a…
A: The strain in the wire is strain=LΔL=2.43×10−4Explanation:Step 1: Given- The mass of the stone is…
Q: The figure represents an insect caught at the midpoint of a spider-web thread. The thread breaks…
A: Given,breaking stress of the string, 9.2 ×108 N/m2strain, 2.00lengthh of the thread, L = 3.0 cmcross…
Q: Ropes for rock climbing have a diameter of 10.5 mm and a Young's modulus of 8.72x10 N/m2. If a rock…
A: Given: Diameter,d=10.5mm=10.5×10-3mRadius,r=5.25mm=5.25×10-3mYoung's…
Q: An 11.0-kg stone at the end of a steel (Young's modulus 2.0 x 1011 N/m²) wire is being whirled in a…
A:
Q: The Young's modulus for aluminium is 7 × 10¹0 Pa. You want an aluminium wire to not stretch more…
A: Given data: Young's modulus (Y) = 7×1010 Pa Stretch in wire (ΔL) = 1.8 cm = 0.018 m Original Length…
Q: ) A 54 kg diver is at the end of a diving board. That is 3.8 m long and has a mass of 26 kg. What is…
A:
Q: A mineshaft has an ore elevator hung from a single braided cable of diameter 2.5 cm. Young’s modulus…
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Q: A cable is 100 m long and has a cross-sectional area of 1.0 x 10-6 m2. A 1000 N force is applied to…
A: The objective of the question is to find out how far the cable stretches when a force is applied to…
Q: A 557-N force is applied to stretch a cable, 66-m long and has a cross-sectional area of 2.8 mm^2.…
A: Given F=557 N L=66m A=2.8 mm2 Y=1.0x10^11 N/m2
Q: An 9.85-kg stone at the end of a steel (Young's modulus 2.0 x 10 N/m²) wire is being whirled in a…
A: We have the Young's modulus Y=stressstrain
Q: Suppose a person’s femoral diaphysis is idealized as a circular cylinder with a periosteal diameter…
A:
Q: The truss is composed of equilateral triangles of side a-1.9 m. The load is L=310 N. Determine the…
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Q: The right end of a horizontal beam of mass 4kg and length 3.3m is fixed to a wall by a hinge. The…
A: This is a problem regarding the equilibrium of forces and torques. The figure for the problem can be…
Q: Assume Young's modulus for bone is 1.50 x 1010 N/m2. The bone breaks if stress greater than 1.50 x…
A: Given : Young's modulus for bone, Y = 1.50*1010 N/m2 Stress to break the bone, S =…
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- The figure shows an approximate plot of stress versus strain for a spider-web thread, out to the point of breaking at a strain of 2.20. The vertical axis scale is set by a = 0.160 GN/m²,b = 0.500 GN/m?, and c = 0.720 GN/m². Assume that the thread has an initial length of 0.700 cm, an initial cross-sectional area of 7.00 × 10-12 m², and (during stretching) a constant volume. The strain on the thread is the ratio of the change in the thread's length to that initial length, and the stress on the thread is the ratio of the collision force to that initial cross-sectional area. Assume also that when the single thread snares a flying insect, the insect's kinetic energy is transferred to the stretching of the thread. (a) How much kinetic energy would put the thread on the verge of breaking? What is the kinetic energy of (b) a fruit fly of mass 5.50 mg and speed 2.20 m/s and (c) a bumble bee of mass 0.440 g and speed 0.840 m/s? Would (d) the fruit fly and (e) the bumble bee break the thread?…The legs of a weight lifter must ultimately support the weights he has lifted. A human tibia (shinbone) has a circular cross section of approximately 3.6 cm outer diameter and 2.5 cm inner diameter. (The hollow portion contains marrow. ) if a 90 kg lifter stands on both legs, what is the heaviest weight he can lift without breaking his legs, assuming that the breaking stress of the bone is 200 MPa?The beam supports the loading shown. Determine the state of stress at points E and F at section a-a.
- A hollow cortical bone has a maximum compressive stress of 185 MPa. This bone has an area of 6.4 cm². What is the maximum force this bone can withstand in compression, in Newtons?A man with a mass of 72.1 kg stands on one foot. His femur has a cross-sectional area of 8.00 cm2 and an uncompressed length 49.6 cm. Young’s modulus for compression of the human femur is 9.40 × 109 N/m2. A.) How much shorter is the femur when the man stands on one foot? B.)What is the fractional length change of the femur when the person moves from standing on two feet to standing on one foot?Assume a human leg contains a 50cm long bone with an average cross section of 3cm. By how much (in micrometres) does the bone shorten when the entire body weight of the person is supported by that one leg. The body weight is 700N and the Young's modulus for bone is 1.8 x 1010 Pa Answer:
- The table shown in the image below shoes the stress and strain values (in MPa) for a silk spider thread. Using the linear part of the curve, calculate the Young’s modulus for the spider silk. (Hint: First plot a stress versus strain curve for the data shown) Title of table is: Stress (MPa) strain10. Ā = -2â + -3ŷ and B = -4â + -4ŷ. Calculate R = Ã+B. Calculate 0, the direction of R. Recall that 0 is defined as the angle with respect to the +x-axis. A. 49.4° B. 130.6° C. 229.4° D. 310.6°The figure shows the stress-strain curve for a material. The scale of the stress axis is set by s = 300, in units of 106 N/m². What are (a) the Young's modulus and (b) the approximate yield strength for this material? Assume & = 0.0010. (a) Number (b) Number 1.5E11 Hint 3E8 eTextbook and Media Stress (10 N/m²) E Strain Units 28 N/m^2 or Pa Units N/m^2 or Pa SUPPORT
- The change in dimension of an object under application of external force is strain Is given by the strain ε. Is this statement correct?Structural member AB is to be supported by a strut CD. Determine the smallest length CD may have, and specify where D must be located for a strut of this length to be used. Take x= 120 mm. 60 mm D. y 20 mm E The smallest length CD may have is mm. The coordinates of point Dare ( and Imm.Suppose a person’s femoral diaphysis is idealized as a solid circular cylinder with a diameter of 2 cm. The ultimate stress in tension is 120×106 pa. Calculate the maximal tension force the femoral diaphysis can sustain.