A vehicle is purchased for $45000. If the vehicle depreciates (loses value) at a rate of 20 percent per year, determine the value of the vehicle after 6 years. Round answer to the nearest cent. $

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Problem Statement:**

A vehicle is purchased for $45,000. If the vehicle depreciates (loses value) at a rate of 20 percent per year, determine the value of the vehicle after 6 years. Round your answer to the nearest cent.

**Solution:**

To solve this problem, you will use the formula for depreciation:

\[ \text{Future Value} = \text{Present Value} \times (1 - \text{Depreciation Rate})^{\text{Number of Years}} \]

Given:
- Present Value = $45,000
- Depreciation Rate = 20% = 0.20
- Number of Years = 6

**Step-by-Step Calculation:**

1. Substitute the values into the equation:
   \[ \text{Future Value} = 45000 \times (1 - 0.20)^6 \]

2. Calculate \(1 - 0.20 = 0.80\).

3. Raise 0.80 to the power of 6:
   \[ 0.80^6 = 0.262144 \]

4. Multiply by the present value:
   \[ 45000 \times 0.262144 = 11796.48 \]

The value of the vehicle after 6 years is approximately **$11,796.48**.
Transcribed Image Text:**Problem Statement:** A vehicle is purchased for $45,000. If the vehicle depreciates (loses value) at a rate of 20 percent per year, determine the value of the vehicle after 6 years. Round your answer to the nearest cent. **Solution:** To solve this problem, you will use the formula for depreciation: \[ \text{Future Value} = \text{Present Value} \times (1 - \text{Depreciation Rate})^{\text{Number of Years}} \] Given: - Present Value = $45,000 - Depreciation Rate = 20% = 0.20 - Number of Years = 6 **Step-by-Step Calculation:** 1. Substitute the values into the equation: \[ \text{Future Value} = 45000 \times (1 - 0.20)^6 \] 2. Calculate \(1 - 0.20 = 0.80\). 3. Raise 0.80 to the power of 6: \[ 0.80^6 = 0.262144 \] 4. Multiply by the present value: \[ 45000 \times 0.262144 = 11796.48 \] The value of the vehicle after 6 years is approximately **$11,796.48**.
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