A vapour compression refrigerator circulates 4.5 kg of NH, per hour, condensation take place at 30°C and evaporation at -15°C. There is no under-cooling of the refrigerant. The temperature after isentropic compression is 75°C and specific heat of superheated vapour is 2.82 kJ/kgK. Determine: i) COP. ii) Ice produces in kg per hour in the evaporator from water at 20°C and ice at 0°C. Take: enthalpy of fusion of ice = 336 kJ/kg.
A vapour compression refrigerator circulates 4.5 kg of NH, per hour, condensation take place at 30°C and evaporation at -15°C. There is no under-cooling of the refrigerant. The temperature after isentropic compression is 75°C and specific heat of superheated vapour is 2.82 kJ/kgK. Determine: i) COP. ii) Ice produces in kg per hour in the evaporator from water at 20°C and ice at 0°C. Take: enthalpy of fusion of ice = 336 kJ/kg.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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LTE2 KB/s
4G
4G
3:43
64
+ IIl yr RAC - Tes... /
Government College of Engineering, Salem-11
Department of Mechanical Engineering
Sub Code:16PTME303 Sub Name: Refrigeration and Air Conditioning
UNIT TEST –I
Date: 23/092020
Class: B.E PT Mechanical Engineering
Marks:50
Semester: III
Duration:90 min
PART – A
Q. No
Question
M
BT
CO
L
1
Draw T-S and P-h diagram for Vapour compression cycle with vapour wet
after compression.
1
1-F
Define ton of refrigeration.
2
1-F
1
Determine the COP of a refrigerating machine working on a reversed Carnot
cycle operates between 310K and 250K.
3
2
1-
1
A
4
2
1-
2
Classify the refrigerant evaporators
A
2
1-
2
State the merits and demerits of air-refrigeration system.
U
PART- B
M
BT
CO
A vapour compression refrigerator circulates 4.5 kg of NH3 per hour, | 15
condensation take place at 30°C and evaporation at -15°C. There is no
under-cooling of the refrigerant. The temperature after isentropic
compression is 75°C and specific heat of superheated vapour is 2.82
kJ/kgK. Determine: i) COP. ii) Ice produces in kg per hour in the
evaporator from water at 20°C and ice at 0°C. Take: enthalpy of
fusion of ice = 336 kJ/kg.
An ammonia vapour-compression refrigerator operates between an
evaporator pressure of 2.077 bar and a condenser pressure of 12.37
bar. The following cycles are to be compared; in each case there is no
undercooling in the condenser, and the isentropic compression may be
assumed: i) The vapour has a dryness fraction if 0.9 at entry to the
compressor. ii) The vapour is dry saturated at entry to the compressor.
iii) The vapour has 5K of superheat at entry to the compressor. In each
case calculate COP and the refrigeration effect per kg.
With a neat sketch, explain the working principle of Vapour compression| 10
refrigeration and state the functions of each component.
6
1-
1
A
7
15
1-
1
U
8
3-F
1
М-Marks
Blooms Taxonomy Level (BTL)
Levels used in Mechanical Curriculum
1.Knowledge
Familiarity(F)
2. Comprehension
3. Application
Usage(U)
2."
Transcribed Image Text:Vo) 1 0.00
LTE2 KB/s
4G
4G
3:43
64
+ IIl yr RAC - Tes... /
Government College of Engineering, Salem-11
Department of Mechanical Engineering
Sub Code:16PTME303 Sub Name: Refrigeration and Air Conditioning
UNIT TEST –I
Date: 23/092020
Class: B.E PT Mechanical Engineering
Marks:50
Semester: III
Duration:90 min
PART – A
Q. No
Question
M
BT
CO
L
1
Draw T-S and P-h diagram for Vapour compression cycle with vapour wet
after compression.
1
1-F
Define ton of refrigeration.
2
1-F
1
Determine the COP of a refrigerating machine working on a reversed Carnot
cycle operates between 310K and 250K.
3
2
1-
1
A
4
2
1-
2
Classify the refrigerant evaporators
A
2
1-
2
State the merits and demerits of air-refrigeration system.
U
PART- B
M
BT
CO
A vapour compression refrigerator circulates 4.5 kg of NH3 per hour, | 15
condensation take place at 30°C and evaporation at -15°C. There is no
under-cooling of the refrigerant. The temperature after isentropic
compression is 75°C and specific heat of superheated vapour is 2.82
kJ/kgK. Determine: i) COP. ii) Ice produces in kg per hour in the
evaporator from water at 20°C and ice at 0°C. Take: enthalpy of
fusion of ice = 336 kJ/kg.
An ammonia vapour-compression refrigerator operates between an
evaporator pressure of 2.077 bar and a condenser pressure of 12.37
bar. The following cycles are to be compared; in each case there is no
undercooling in the condenser, and the isentropic compression may be
assumed: i) The vapour has a dryness fraction if 0.9 at entry to the
compressor. ii) The vapour is dry saturated at entry to the compressor.
iii) The vapour has 5K of superheat at entry to the compressor. In each
case calculate COP and the refrigeration effect per kg.
With a neat sketch, explain the working principle of Vapour compression| 10
refrigeration and state the functions of each component.
6
1-
1
A
7
15
1-
1
U
8
3-F
1
М-Marks
Blooms Taxonomy Level (BTL)
Levels used in Mechanical Curriculum
1.Knowledge
Familiarity(F)
2. Comprehension
3. Application
Usage(U)
2.
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