A vacuum residue of Conradson carbon wt. 16% CCR is fed into delayed coker at rate of 100,000 lb./hr., of API-9 and with sulfur content of 3 wt. %. Find the amount of yield (Ib/hr) and their sulfur content. Calculate yield of liquid Sulfur distribution as follow: Products Gas S (wt. %) 30 LN 1.7 | LGO 15.4 HN HGO Coke 3.3 19.6 30 Gas(C,)wt% = 7.8+0.144 x (wt% CCR) = 11.29 + 0.343 x (wt% CCR) Naphtha wt% Coke wt% = 1.6 x (wt% CCR) %3D Gas oil wt% = 100 - Gas wt% - Naphtha wt%- Coke wt% %3D

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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A vacuum residue of Conradson carbon wt. 16% CCR is fed into delayed
coker at rate of 100,000 lb./ hr., of API=9 and with sulfur content of 3 wt. %. Find
the amount of yield (Ib/hr) and their sulfur content. Calculate yield of liquid
Sulfur distribution as follow:
|LGO
15.4
Products
| LN
HN
HGO
19.6
30
Gas
Coke
S (wt. %)
| 30
1.7
3.3
Gas(C, )wt% = 7.8 +0.144 x (wt% CCR)
Naphtha wt% = 11.29 + 0.343 x (wt% CCR)
Coke wt% = 1.6 x (wt% CCR)
Gas oil wt% = 100 – Gas wt% – Naphtha wt% – Coke wt%
Transcribed Image Text:A vacuum residue of Conradson carbon wt. 16% CCR is fed into delayed coker at rate of 100,000 lb./ hr., of API=9 and with sulfur content of 3 wt. %. Find the amount of yield (Ib/hr) and their sulfur content. Calculate yield of liquid Sulfur distribution as follow: |LGO 15.4 Products | LN HN HGO 19.6 30 Gas Coke S (wt. %) | 30 1.7 3.3 Gas(C, )wt% = 7.8 +0.144 x (wt% CCR) Naphtha wt% = 11.29 + 0.343 x (wt% CCR) Coke wt% = 1.6 x (wt% CCR) Gas oil wt% = 100 – Gas wt% – Naphtha wt% – Coke wt%
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