A vacuum diode is shown at right. The heated cathode emits electrons into the region between two parallel plates, where they travel towards the anode. For a fixed anode voltage Vo, the system reaches a steady-state described by a static charge distribution p(x). The plates are separated by a distance a, and the electrostatic potential is cathode Þ(x)=√₁(x/a) 4/3 0 Find the electric field vector E and charge density p(x) between the plates. + p(x) a anode
A vacuum diode is shown at right. The heated cathode emits electrons into the region between two parallel plates, where they travel towards the anode. For a fixed anode voltage Vo, the system reaches a steady-state described by a static charge distribution p(x). The plates are separated by a distance a, and the electrostatic potential is cathode Þ(x)=√₁(x/a) 4/3 0 Find the electric field vector E and charge density p(x) between the plates. + p(x) a anode
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Expert Solution
Step 1
We have given a expression for potential.
We know that the electric field can be written as the negative gradient of potential and the other concepts is that the possion equation.
By using these two concepts we can solve the given problem as following in step two.
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